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3 years ago

9

A rabbit runs 28 m toward the left in 9 s; then the rabbit suddenly changes direction and runs 18 m toward the right in the next

5 s. What was its average speed for the first 9 s?

1 answer:

Viefleur [7K]3 years ago

8 0

Answer:

The answer is 3.111111.

Explanation:

It runs 28 m in the first 9 s, and 28 divided by 9 equals 3.1 and the one goes on forever.

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Which composition of water moves to begin a deepwater current?

Paraphin [41]

<u>Answer:</u>

<h2>Cold, Salty water.</h2>

<u>Explanation:</u>

The cold, salty ocean water is denser than the warmer water. Because of higher density, cold water sinks into the bottom of the ocean while warm water remains at the surface.

The sinking of the cold water at depth moving away from the surface generates deepwater currents by a process called upwelling. These deepwater currents bring the nutrient-rich water at the surface providing food and nutrients to marine life.

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3 years ago

Calculate the amount of heat needed to raise the temperature of 200g of ice from-30°C 50C water. (C = .5 for ice, C 1 for water,

Nitella [24]

<u>Answer:</u> The amount of heat needed is 29000 Cal.

<u>Explanation:</u>

The process involved in this problem are:

$(1):H_2O(s)(-30^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(50^oC)$

Now, we calculate the amount of heat released or absorbed in all the processes.

<u>For process 1:</u>

$q_1=mC_{p,s}\times (T_2-T_1)$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of ice = 200 g

$T_2$ = final temperature = $0^oC$

$T_1$ = initial temperature = $-30^oC$

Putting all the values in above equation, we get:

$q_1=200g\times 0.5Cal/g^oC\times (0-(-30))^oC=3000Cal$

<u>For process 2:</u>

$q_2=m\times L_f$

where,

$q_1$ = amount of heat absorbed = ?

m = mass of water or ice = 200 g

$L_f$ = latent heat of fusion = 80 Cal/g

Putting all the values in above equation, we get:

$q_2=200g\times 80Cal/g=16000Cal$

<u>For process 3:</u>

$q_3=m\times C_{p,l}\times (T_{2}-T_{1})$

where,

$q_3$ = amount of heat absorbed = ?

m = mass of water = 200 g

$T_2$ = final temperature = $50^oC$

$T_1$ = initial temperature = $0^oC$

Putting all the values in above equation, we get:

$q_3=200g\times 1Cal/g^oC\times (50-0)^oC=10000Cal$

Calculating the total heat absorbed, we get:

$Q=q_1+q_2+q_3$

$Q=3000+16000+10000=29000Cal$

Hence, the amount of heat needed is 29000 Cal.

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3 years ago

When moving a couch, you exert a force of 400N and push it 4.0m. How much work have you done on the couch?

Aleks04 [339]

Answer:

Explanation: work equals force times distance so 400x4=1600 joules

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3 years ago

The energy from the movement of electrons through the electron transport chain is directly used to synthesize atp.

baherus [9]

Answer:

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This statement is false

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3 years ago

A current of 0.8 A flows through the motor for 3 minutes. Calculate the total charge in this time.

mixas84 [53]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given terms are :

Current = 0.8 Amperes

Time = 3 minutes = 3 × 60 = 180 seconds

we know that,

$current = \dfrac{charge}{time}$

now, let's solve for charge (q) :

$0.8 = \dfrac{q}{180}$

$q = 180 \times 0.8$

$q = 144 \:$

Total Charge (q) = 144 Coulombs

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3 years ago