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ziro4ka [17]
3 years ago
9

A rabbit runs 28 m toward the left in 9 s; then the rabbit suddenly changes direction and runs 18 m toward the right in the next

5 s. What was its average speed for the first 9 s?
Physics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

The answer is 3.111111.

Explanation:

It runs 28 m in the first 9 s, and 28 divided by 9 equals 3.1 and the one goes on forever.

You might be interested in
How are chemical changes of matter related to the organization of the periodic table
Charra [1.4K]
As elements in period are arranged according to increasing atomic weight with isotope as protium deuterium and trotium of h2 so chemical property are same but physical property different in period ic table
5 0
3 years ago
Chris shoots an arrow up into the air. The height of the arrow is given by the function h(t) = - 16t2 + 32t + 26 where t is the
seropon [69]

Answer:

The maximum height of the arrow is 42 (and the units given for the height)

Explanation:

Everything is easier if you make a graph, you can give values to t and replace that values in the function, for example:

When t=0

h(0)=-16(0^{2})+32(0)+26

h(0)=26

If you give some values to t you can see how the trajectory of the arrow is (please look the graphic below)

Now, to find the maximum you have to find the derivative of the function that describes the height of the arrow:

h(t)=-16t^{2}+32t+26

h'(t)=-32t+32

Then you have to take the derivative, and equals to zero to find t:

-32t+32=0

-32t=32

t=1

That is in the time of 1 second the arrow has its maximum height.

Now you have to replace this value in the original function, to find the height of the arrow:

h(1)=-16(1^{2})+32(1)+26

h(1)=-16+32+36

h(1)=42

4 0
3 years ago
A girl throws a tennis ball upward with an initial velocity of 4 m/s. What is the maximum displacement of the ball?
Jobisdone [24]

Answer:

0.82 m

Explanation:

The ball is in free fall - uniform accelerated motion with constant acceleration downward, a=g=-9.8 m/s^2 (acceleration of gravity). So we can use the following suvat equation to solve the problem:

v^2-u^2=2as

where

v is the final velocity

u = 4 m/s is the initial velocity

a is the acceleration

s is the displacement

At the maximum displacement, v = 0 (the velocity becomes zero). Substituting and solving for s, we find:

s=-\frac{u^2}{2a}=-\frac{4^2}{2(-9.8)}=0.82 m

8 0
3 years ago
The linear impulse delivered by the hit of a boxer is 202 N · s during the 0.244 s of contact. What is the magnitude of the aver
zlopas [31]

Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.

Mathematically it is given by the relation:

Impulse = Force \times Time

According to the numerical values given in the question, I = 202 Ns and T = 0.244 s

So, Force F = \frac{Impulse}{Time} = \frac{202}{0.244} = 827.86 N

Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

7 0
3 years ago
Please help me out as soon as you can. Really need help.
olga nikolaevna [1]
The answer would be 6 because 2.0x3= 6

(newton’s 2nd law)

mark me brainliest
4 0
3 years ago
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