All categories

3 years ago

If you add 50.0 mL of water to a beaker containing 22 mL of water, then how much water do you have in the beaker?

Physics

1 answer:

saw5 [17]3 years ago

6 0

Answer:

72 mL

Explanation:

if you add 50.0 mL of water to a beaker containing 22 mL of water, then the total in the beaker is 50.0 + 22 = 72 mL

You might be interested in

Which of the following substance are not formed by chemical bonds

Sliva [168]

<span>Which of the following substance are not formed by chemical bonds? </span>A MIXTURE

3 0

3 years ago

I need help with these questions.

strojnjashka [21]

I'll go ahead and answer the ones here without an answer. For reference, the half-life formula is <em>final amount = original amount(1/2)^(time/half-life)</em>

<em />

4) 12.5g

x = 100(1/2)^(63/21)

5) 50g

3.125 = x(1/2)^(0.1/0.025)

6) 500g

x = 4000(1/2)^(525/175)

7) 0.24g

0.06 = x(1/2)^(11430/5730)

8) 125g

x = 1000(1/2)^(17100/5700)

Hope this helps! :)

4 0

3 years ago

Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average

MissTica

Answer:

reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year

Explanation:

given data

electricity consume = 14000 kWh

fuel consume = 900 gal

CO₂ produced of fuel = 26.4 lbm/gal

CO₂ produced of electricity = 1.54 lbm/kWh

oil and electricity usage = 21 percent

to find out

the reduction in the amount of CO₂ emissions

solution

we calculate the amount of CO₂ produce here that is

amount of CO₂ produce = ( electricity consume×CO₂ produce electricity + fuel consume × CO₂ consume fuel ) ........................1

put here value

amount of CO₂ produce = ( 14000 × 1.54 + 900 × 26.4 )

amount of CO₂ produce = 45320 lbm/yr

we know reduction is 21%

reduction in amount of CO₂ produced is

reduction in CO₂ produced = 45320 × 21%

reduction in CO₂ produced = 9517.2 lbm per year

so reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year

3 0

3 years ago

A child lies on his back and raises his head up off the floor. When doing so, the total tension force in his neck muscles is 51.

Margarita [4]

Answer:

The total tension in the child's neck muscle, T = 56.51 N

Explanation:

Let m = mass of the child's neck

Radius of the curve, r = 2.40 m

The child's speed, v = 3.35 m/s

The tension force on the child's neck when he raises his head up off the floor, $T_{f} = 51.0 N$

The tension force on the child's neck when he raises his head from the wall of the slide, $T_{s} = ?$

$T_{f} = mg\\g = 9.8 m/s^2\\51 = m * 9.8\\m = 51/9.8\\m = 5.2 kg$

Since he makes a circular turn in water, the radial acceleration can be given by the equation:

$a_{r} = \frac{v^{2} }{r} \\a_{r} = \frac{3.35^{2} }{2.4}\\a_{r} = 4.68 m/s^2$

$T_{s} = ma_{r} \\T_{s} = 5.2 * 4.68\\T_{s} = 24.336 N$

The total tension in the child's neck muscle till be calculated as:

$T = \sqrt{T_{f} ^{2} + T_{s} ^{2} } \\T = \sqrt{51 ^{2} + 24.336^{2} }\\T = \sqrt{2601 + 592.24 }\\T = 56.51 N$

5 0

3 years ago

A distant astronomical object (a quasar) is moving away from us at half the speed of light. what is the speed of the light we re

Aloiza [94]

For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar is mathematically given as c = 3x108 m/s

<h3>What is the speed of light?</h3>

Generally, the equation for the is mathematically given as

The speed of light can be said to be measured to be approximately the value c = 3x108 m/s

In conclusion, An will not influence 3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to 3x108 m/s