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Allushta [10]
3 years ago
5

If you add 50.0 mL of water to a beaker containing 22 mL of water, then how much water do you have in the beaker?

Physics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

72 mL

Explanation:

if you add 50.0 mL of water to a beaker containing 22 mL of water, then the total in the beaker is 50.0 + 22 = 72 mL

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What happens to the electric potential energy of a negatively charged ion as it moves through the water from the negative probe
Nataly [62]

Answer:

Decreases.

Explanation:

Electric potential energy is the potential energy which is associated with the configuration of points charge in a system and it is the result of conservative coulomb force.

When the negatively charge ion is at the position of the negative probe than its potential energy is positive when it is move towards the positive probe it's potential energy becomes negative due to the negative ion.

Therefore, potential energy is decreases when negative charge ion moves through the water from negative probe to positive probe.

5 0
3 years ago
Which of the following is not a form of an inclined plane?
disa [49]

Answer: piece of paper cut into a triangle  

Explanation:

A plane surface lifted at an angle to horizontal from one edge is said to be an inclined plane. A wedge, a ramp or a screw are examples of a forms of inclined plane. A screw is like a inclined plane wound on a cylinder. These are simple machines. On the other hand, a piece of paper cut into a triangle is not an inclined plane as it does rise at an angle from horizontal. It is not a machine.

8 0
3 years ago
Read 2 more answers
A 1.00 x 104 W electric motor is used to lift a
Alexus [3.1K]

Answer: 52%

Explanation:

1W = 1 J/s

motor input is 10000 J/s

Potential energy change

PE = 955(9.81)(25.0) = 234,213.75

power needed to change the PE in that time

P = 234,213.75/ 45 = 5,204.75 Watts

motor is 5204.75 / 10000 = 0.520475 or 52% efficient

4 0
3 years ago
Describe the location of point a. explain what you used as a reference point for you your location
Gwar [14]
I used rise and run to see where point a lies .
That's kind of an answer you could you right?
3 0
3 years ago
In a grandfather clock, the second hand moves forward by one second for each half period of the clock’s pendulum.
Maurinko [17]

To solve the problem it is necessary to take into account the concepts related to simple pendulum, i.e., a point mass that is suspended from a weightless string. Such a pendulum moves in a harmonic motion -the oscillations repeat regularly, and kineticenergy is transformed into potntial energy and vice versa.

In the given problem half of the period is equivalent to 1 second so the pendulum period is,

T= 2s

From the equations describing the period of a simple pendulum you have to

T = 2\pi \sqrt{\frac{L}{g}}

Where

g= gravity

L = Length

T = Period

Re-arrange to find L we have

L = \frac{gT^2}{4\pi^2}

Replacing the values,

L = \frac{(9.8)(2)^2}{4\pi^2}

L = 0.99m

In the case of the reduction of gravity because the pendulum is in another celestial body, as the moon for example would happen that,

T = 2\pi \sqrt{\frac{L}{g/6}}

T = 2\pi\sqrt{\frac{6L}{g}}

T = 2\pi \sqrt{\frac{6*0.99}{9.8}}

T  = 4.89s

In this way preserving the same length of the rope but decreasing the gravity the Period would increase considerably.

6 0
3 years ago
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