ANSWER
EXPLANATION
First, let us make a sketch of the question:
From the diagram:
=> black line represents North
=> green line represents East
=> blue line represents West
=> red line represents South
From the diagram, we see that at the end of his journey, he returns to his start point.
Since displacement is the measure of the change in the position of an object and the boy's position did not change after the journey, his displacement is:
1. bleus
2. rouges
3. petites
4. actifs
5. gross
Just add an -s to make it plural
The (NPN) transistor in this circuit is used to <em>switch a current</em>. When it switches current ON ... acting like a closed switch ... the light goes on.
It's kind of mystifying WHY all of this technological complexity is necessary. There's already a switch in the circuit ... (the two little circles above the 1K resistor in the base circuit with the tilted line between them). That switch could just as well be used, in place of the transistor, to directly switch the current through the light. Why use one switch to control a transistor to make it behave like another switch ? ?
The only actual necessity for doing this that makes sense is if the switch in the base circuit is a tiny low-power switch, and the transistor is a big moose high-power transistor, controlling a high-current, multi-kilowatt searchlight.
A place you might actually find an application like this would be in your car. A small current through the ignition switch behind the key is used to turn on a high-power transistor under the hood, which controls the huge current to the starter motor. That way, they avoid running a 100-Ampere cable in and out of the ignition switch, and needing a several-hundred-Ampere switch in the steering column behind the key.
Answer:
<h2>122kg</h2>
Explanation:
Using the law of conservation of momentum which states that 'the sum of momentum of bodies before collision is equal to their sum after collision. The bodies will move together with a common velocity after collision.
Momentum = Mass * Velocity
<u>Before collision;</u>
Momentum of receiver m1u1= 0 kgm/s (since the receiver is standing still)
Momentum of the tackler
m2u2 = 2.60*122 = 317.2 kgm/s
where m2 and u2 are the mass and velocity of the tacker respectively.
Sum of momentum before collision = 0+317.2 = 317.2 kgm/s
<u>After collision</u>
Momentum of the bodies = (m1+m2)v
v = their common velocity
m1 = mass of the receiver
Momentum of the bodies = (122+m1)(1.30)
Momentum of the bodies = 158.6+1.30m1
According to the law above;
317.2 = 158.6+1.30m1
317.2-158.6 = 1.30m1
158.6 = 1.30m1
m1 = 158.6/1.30
m1 = 122kg
The mas of the receiver is 122kg
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