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anyanavicka [17]
3 years ago
10

Ammonium perchlorate is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas , ch

lorine gas , oxygen gas , water , and a great deal of energy.
What mass of water is produced by the reaction of of ammonium perchlorate?
Chemistry
1 answer:
Zinaida [17]3 years ago
3 0

Answer:

2.9 g

Explanation:

There is some info missing. I think this is the original question.

<em>Ammonium perchlorate is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas, chlorine gas, oxygen gas, water, and a great deal of energy. </em>

<em>What mass of water is produced by the reaction of </em><em>9.6 g</em><em> of ammonium perchlorate?</em>

<em />

Step 1: Given data

Mass of ammonium perchlorate: 9.6 g

Step 2: Write the balanced equation

2 NH₄ClO₄(s) → N₂(g) + Cl₂(g) + 2 O₂(g) + 4 H₂O(l)

Step 3: Calculate the moles corresponding to 9.6 g of ammonium perchlorate

The molar mass of ammonium perchlorate is 117.49 g/mol.

9.6 g \times \frac{1mol}{117.49 g} = 0.082mol

Step 4: Calculate the moles of water formed from 0.082 moles of ammonium perchlorate

The molar ratio of NH₄ClO₄ to H₂O is 2:4. The moles of water formed are 4/2 × 0.082 mol = 0.16 mol

Step 5: Calculate the mass corresponding to 0.16 moles of water

The molar mass of water is 18.02 g/mol.

0.16 mol \times \frac{18.02g}{mol} = 2.9 g

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Problem PageQuestion A chemistry student weighs out of acetic acid into a volumetric flask and dilutes to the mark with distille
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Answer:

7.92 mL

Explanation:

There is some info missing. I think this is the original question.

<em>A chemistry student weighs out 0.0617g of acetic acid (HCH₃CO₂) into a 250.mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1300 M NaOH solution. </em>

<em> Calculate the volume of solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits.</em>

<em />

First, we will calculate the moles of acetic acid (MW 60.05 g/mol).

0.0617 g × (1 mol/60.05 g) = 1.03 × 10⁻³ mol

Let's consider the neutralization reaction between HCH₃CO₂ and NaOH.

HCH₃CO₂ + NaOH ⇄ NaCH₃CO₂ + H₂O

The molar ratio of HCH₃CO₂ to NaOH is 1:1. The moles of NaOH are 1.03 × 10⁻³ moles.

The volume of 0.1300 M NaOH that contains 1.03 × 10⁻³ mol is:

1.03 × 10⁻³ mol × 1000 mL/0.1300 mol = 7.92 mL

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Could volume by displacement be used to determine the volume of a lump of rock salt? Explain would be nice
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Yes it could, but you'd have to set up the process very carefully.
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1).  Displacement of water would not be a wise method, since rock salt
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So you would have to choose some other fluid besides water ... one in
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2).  Whatever fluid you did choose, it would also have to be less dense
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