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Nata [24]
3 years ago
11

A solution is prepared by dissolving 0.23 mol of benzoic acid and 0.27 mol of sodium benzoate in water sufficient to yield 1.00

L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to drop slightly. The pH does not decrease drastically because the NaOH reacts with the _present in the buffer solution. The Ka of benzoic acid is 1.36 x 10-3 A) H20 B) H30+ C) benzoate ion D) benzoic acid E) This is a buffer solution: the pH does not change upon addition of acid or base.
Chemistry
1 answer:
Monica [59]3 years ago
7 0

Answer:

The pH does not decrease drastically because the NaOH reacts with the <u>D) Benzoic acid</u> present in the buffer solution.

Explanation:

The hydroxide ions will react with acidic part of the solutions, it means the benzoic acid, so it will form the conjugate base, the benzoate ion.

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Question 6 (3 points)
olga55 [171]

Answer:

Explanation:

Given parameters:

Molarity of KOH = 0.26M

Volume of H₂SO₄ = 19.76mL

Molarity of H₂SO₄ = 0.20M

Unknown:

Volume of KOH = ?

Solution:

This is a neutralization reaction in which an acid reacts with a base to produce salt and water:

         H₂SO₄     +     2KOH      →    K₂SO₄    +     2H₂O

 We solve from the known to the unknown in the reaction.

The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:

       Number of moles of acid = molarity x volume

       Number of moles of acid = 19.76 x 0.20 = 3.95mol

From the balanced reaction equation:

      1 mole of acid reacts with 2 moles of the bases KOH

     3.95mole of acid would react with 3.95moles x 2 of the base

  Number of moles of reacting base = 7.90moles

To find the volume of base;

  Volume of base = \frac{number of moles of base}{molarity}

   Volume = \frac{7.90}{0.26} = 30.40mL

Learn more:

Neutralization brainly.com/question/6447527

#learnwithBrainly

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