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3 years ago

8

Why is Mars visible from earth in the night sky

1 answer:

Studentka2010 [4]3 years ago

7 0

<span>You can see mars in the night sky because it is a very bright planet. Mars is as bright, or brighter than the stars. Yes, all planets are pretty bright, but mars in beyond bright along with jupiter, mercury, etc. Hope this helped! :)</span>

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If you have 8.56 g of H2, how many grams of NH3 can be produced?

Lyrx [107]

<span>N2 + 3H2 → 2 </span>NH3<span> from bal. rxn., 2 moles of </span>NH3<span> are formed per 3 moles of </span>H2, 2:3 moleH2<span>: 3.64 </span>g<span>/ 2 </span>g<span>/mole </span>H2<span>= 1.82 1.82 moles </span>H2<span> x 2/3 x 17

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4 0

3 years ago

How did Mendeleev set up his Periodic Table of Elements?

Ksju [112]

He set up his periodic table by the atomic mass

8 0

2 years ago

What would be the volume in millilitres of a blood sample of 2.15 microliters (ul)?

Zanzabum

2.15 x 10⁻³mL

Explanation:

Given parameter:

Volume of blood sample in uL = 2.15uL

Conversion uL → mL

micro- and milli- are both prefixes of sub-units.

liter is a unit of volume of a substance.

micro - is 10⁻⁶

milli- is of the order 10⁻³

The problem is converting from micro to milli:

if we multiply 10⁻⁶ by 10³ we would have our milli;

1000uL = 1mL

2.15uL : 2.15uL x $\frac{1mL}{1000uL}$ = 2.15 x 10⁻³mL

learn more:

Volume brainly.com/question/5055270

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4 0

3 years ago

Assuming the input of energy continues for another 5.0 seconds, where will the particle be?

konstantin123 [22]

The answer is A. Equilibrium

3 0

3 years ago

At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat

wariber [46]

Answer:

0.808 M

Explanation:

Using Raoult's Law

$\frac{P_s}{Pi}= x_i$

where:

$P_s$ = vapor pressure of sea water( solution) = 23.09 mmHg

$P_i$ = vapor pressure of pure water (solute) = 23.76 mmHg

$x_i$ = mole fraction of water

∴

$\frac{23.09}{23.76}= x_i$

$x_i = 0.9718$

$x_i+x_2=1$

$x_2 = 1- x_i$

$x_2 = 1- 0.9718$

$x_2 = 0.0282$

$x_i = \frac{n_i}{n_i+n_2}$ ------ equation (1)

$x_2 = \frac{n_2}{n_i+n_2}$ ------ equation (2)

where; $(n_2) =$ number of moles of sea water

$(n_i) =$ number of moles of pure water

equating above equation 1 and 2; we have :

$\frac{n_2}{n_i}$ $= \frac{0.0282}{0.9178}$

$= 0.02901$

NOW, Molarity = $\frac{moles of sea water}{mass of pure water }*1000$

$= \frac{0.02901}{18}*1000$

$= 0.001616*1000$

$= 1.616 M$

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have $\frac{1.616}{2} =0.808 M$

3 0

2 years ago

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