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olya-2409 [2.1K]
3 years ago
12

Please help it’s due asap I WILL GIVE BRAINLIEST

Chemistry
1 answer:
inna [77]3 years ago
4 0
I think it’s number 5 and number 9 hopes this helps.
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A solution is prepared by dissolving 32. 0 g of NiSO4 in water. What current would be needed to deposit all of the nickel in 5.
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The current needed to deposit all of the nickel in 5 hours is 2.219 A

<h3>What is Faraday's Law of electrolysis?</h3>

According to the first law of Faraday, the amount of substance liberated at an electrode is directly proportional to the quantity of charge passed through an electrolyte.

m = zq , where z = electrochemical equivalent

An electrochemical equivalent is the mass of the substance liberated at an electrode when 1 Columb of charge is passed through the electrolyte.

For the nickel,

Ni^{2+} (aq) + 2e^- \rightarrow Ni (s)

z = 2

The molar mass of NiS0₄ = 154.75 g

154.75 g of Ni needs 2 x 96485 C

32 g of Ni needs \frac{2\times 96485\times 32}{154.75} \\

32 g of Ni needs 39944.79 C

We know,

q = It

Where q = charge

I = current and t = time in seconds

q = 39944.79 C and t = 5 x 60 x 60 = 18000 s

I = \frac{q}{t} \\     = \frac{39944.79}{18000}

= 2.219 A

Hence, the current needed to deposit all the nickel is 2.219 A in 5 hours

Learn more about Faraday's law of electrolysis:

brainly.com/question/14548624

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