Convert the condensed structures to line angle formulas: 1. CH3CH2CH(CH3)CH2CH3 8. CH:COCH 9. CH3CH2OCH3 2. CH3CH2CH(CH2CH3)CH(C
H3)CH2CHO CH)CH:CH-CH: 10. CH CH2CH=C(CH:CH)(C(CH))CH 3. CH3CH2CH(CH3)CH(CH3)CH2CH3 11. CH:CH-CH(CH2CH)CH OH 4. CH3C(CH3)2CH2CH2CH(CH3)CH2CH3 12. CHCHOCH2CHO 5. CH(CH3)2CH(CI)CH2CH3 13. HOOCCH2NHCH(CH3)COCH; 6. CH3CH2CHOCH(CH2CH3)CH2CH3 14. HOOCCH OCH COOH 7. HOCH:C(CH3)2CONH2
1 answer:
Answer:
Attached in the photo.
Explanation:
Hello,
The answers in the attached photo. Just three things:
- In the second point a parenthesis is missing to properly understand the molecule (after the oxygen), nevertheless, I assumed it was an ether.
- In the sixth point, there's a missing hydrogen for it to be an ether as well.
- In the tenth point the second parenthesis is not clear, it seems there's a missing subscript, nevertheless I draw it assuming complete octates.
Best regards.
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Answer
The empirical formula is CrO₂Cl₂
Explanation:
Empirical formula is the simplest whole number ratio of an atom present in a compound.
The compound contain, Chromium=33.6%
Chlorine=45.8%
Oxygen=20.6%
And the molar mass of Chromium(Cr)=51.996 g mol.
Chlorine containing molar mass (Cl)= 35.45 g mol.
Oxygen containing molar mass (O)=15.999 g mol.
Step-1
Then,we will get,
Cr= mol
Cl= mol.
O= mol.
Step-2
Divide the mole value with the smallest number of mole, we will get,
Cr=
Cl=
O=
Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)