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12345 [234]
3 years ago
10

Convert the condensed structures to line angle formulas: 1. CH3CH2CH(CH3)CH2CH3 8. CH:COCH 9. CH3CH2OCH3 2. CH3CH2CH(CH2CH3)CH(C

H3)CH2CHO CH)CH:CH-CH: 10. CH CH2CH=C(CH:CH)(C(CH))CH 3. CH3CH2CH(CH3)CH(CH3)CH2CH3 11. CH:CH-CH(CH2CH)CH OH 4. CH3C(CH3)2CH2CH2CH(CH3)CH2CH3 12. CHCHOCH2CHO 5. CH(CH3)2CH(CI)CH2CH3 13. HOOCCH2NHCH(CH3)COCH; 6. CH3CH2CHOCH(CH2CH3)CH2CH3 14. HOOCCH OCH COOH 7. HOCH:C(CH3)2CONH2

Chemistry
1 answer:
kumpel [21]3 years ago
3 0

Answer:

Attached in the photo.

Explanation:

Hello,

The answers in the attached photo. Just three things:

- In the second point a parenthesis is missing to properly understand the molecule (after the oxygen), nevertheless, I assumed it was an ether.

- In the sixth point, there's a missing hydrogen for it to be an ether as well.

- In the tenth point the second parenthesis is not clear, it seems there's a missing subscript, nevertheless I draw it assuming complete octates.

Best regards.

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How are the electron structures of boron (B) and aluminum (Al) similar?
Arte-miy333 [17]

Answer:

C: They both have 1 electron in a p orbital.

Explanation:

Find the electron configuration of B

Boron is 1s 2s2 2p1

Find the electron configuration of Al

Aluminum is 1s2 2s2 2p6 3s2 2p1

If you look at the p orbital, they both have 1 electron.

Therefore, the correct answer is C.

Hope it helped!

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Intermolecular distance is the distance between the particles that make up matter. The graph below compares the intermolecular d
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X is the gas and Y is the liquid. Intermolecular distances are farther apart in gases than in liquids.
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3 years ago
(a) What is the basis of the approximation that avoids using the quadratic formula to find an equilibrium concentration?
rusak2 [61]

The approximation is valid because  is very small.

Calculation of  concentration:

Since

0.85 M        0    0

(0.85-x)M    x      x

Now the value of x should be

x = 0.0000229

So based on this, the above concentration should be determined.

Now you will solve using the quadratic formula instead of iterations, to show that the same value of x is obtained either way. using the quadratic equation to calculate [h3o+] in 0.00250 m hno2, what are the values of a, b, c and x , where a, b, and c are the coefficients in the quadratic equation ax2+bx+c=0, and x is [h3o+]? recall that ka=4.5×10−4 .

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] (1)

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

x = 0.000859

As [H₃O⁺] = x; [H₃O⁺] = 0.000859M

To know more about Equilibrium constant

brainly.com/question/19340344

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<span>4,800 pounds (2,200 kg) of ammonium nitrate fertilizer, nitromethane, and diesel fuel mixture.</span>
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