Answer:
The correct answer is $6934.48.
Explanation:
According to the scenario, the given data are as follows:
Time period ( 41 - 64 years) (n)= 24 years
Rate of interest (r) = 8%
Future value (FV) = $500,000
Annual deposit amount = P
So, we can calculate the annual deposit amount by using following formula:
FV = P × (1+r) × [{ (1+r)^n - 1} ÷ r]
By putting the value, we get
$500,000 = P × ( 1 + 0.08) [{ (1+0.08)^24 - 1} ÷ 0.08]
$500,000 = P × ( 1.08) [{ (1.08)^24 - 1} ÷ 0.08]
$500,000 = P × ( 1.08) [{ 6.34118073724 - 1} ÷ 0.08]
$500,000 = P (72.1035)
P = $500,000 ÷ 72.1035
P = 6934.48
Answer:
i believe the answer is TRUE
Explanation:
Answer:
Full question: <em>On their birthdays, employees at a large company are permitted to take a 60-minute lunch break instead of the usual 30 minutes. Data were obtained from 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday. The company wishes to investigate whether these data provide convincing evidence that the mean time is greater than 60 minutes. Of the following, which information would NOT be expected to be a part of the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance?</em>
<em>Answe</em><em>r: Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
Explanation:
<em>From the given question let us recall the following statements:</em>
<em>Employees at a large company are permitted to take a 60-minute Lunch break instead of the 30 minutes.</em>
<em>Data was gotten from = 10 randomly selected company employees on the amount of time that each actually took for lunch on his or her birthday</em>
<em>Given that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes.</em>
<em>The company tries to investigate the data to know that the mean is greater than 60 minutes</em>
<em>the next step is to find the process of correctly conducting a hypothesis test to investigate the question, at the 0.05 level of significance</em>
<em>Therefore,</em>
<em>Since that the p-value is greater than 0.05, rejecting the null hypothesis and concluding that the mean time was not greater than 60 minutes. </em>
<em>Or</em>
<em>The P-value> 0.05</em>
<em>The mean time is not greater than 60 minutes</em>
Answer:
None of the loss amount in year 2 will be deductible
Explanation:
Based on the information given How the loss will be treated for tax purposes in year 2 is that the LOSS amount will NOT be deductible in Year 2 reason been that tax payer can only collect the deduction in bad debt in the year the bad debt has no real value and become un-useful.
Secondly the tax payer should not wait till the debt is due before knowing whether the bad debt has no real value reason been that bad debt will has no real value when there is no hope that the debt amount that is owed will be paid which is why to a limited extent a non business bad debt that has no real value will not be deductible.
Therefore How the loss will be treated for tax purposes in year 2 is that None of the loss amount in year 2 will be deductible
