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ycow [4]
3 years ago
8

I’m lost for this question

Chemistry
1 answer:
Natasha2012 [34]3 years ago
7 0
An element is all the same thing. Pure, if you will. 

The first one is definitely an element. The second would be a compound (it's atoms are different colors). I would say the last one is an element, since it has ll the same color of atoms. 

I hope this helped you! If you have anymore questions, feel free to ask me. 
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Magnesium is an active metal; it burns in the form of powder, ribbons, and filaments to
dolphi86 [110]

Explanation:

magnesium can be used for the construction as only when the metal is divided into fine pieces or as a thin sheet, magnesium will burn rapidy.

5 0
3 years ago
g The first step in the process is to calibrate the grating, so we know the grating spacing (the distance between the openings i
Trava [24]

Answer:

The grating spacing is  d = 1055nm

Explanation:

From the question we are told that

    The wavelength is  \lambda = 590 nm = 590 *10^{-9}m

    The angle is \theta = 34^0

    The  order of the spectrum is  n = 1

Generally in grating grating the condition for maxima   to occur is  

             d sin \theta  = n \lambda

where d is the grating spacing

     making d the subject of the formula

                  d = \frac{\lambda }{sin \theta }

        Substituting values

                  d = \frac{590 * 10^{-9}}{sin (34)}

                     d = 1055nm

8 0
3 years ago
Given the balanced equation representing a reaction:
Nesterboy [21]

Answer:

It accepted a proton from HCl

Explanation:

When properly written, the equation box the reaction is given as; HCl(aq) + H2O(l) ----> H3O+(aq) + Cl-(aq).

According to Brownstead-Lowry definition of acids and bases, an acid donates protons while a base accepts protons.

Water molecule acts as a base in the reaction because it accepted a proton from HCl in the reaction above.

7 0
3 years ago
I need help answering 14 and 15
Debora [2.8K]

Answer:

14 is D and 15 is C

Explanation:

4 0
4 years ago
2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

7 0
3 years ago
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