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DochEvi [55]
3 years ago
7

Which of the following are the requirements when creating a hypothesis for an experiment? Check ALL that apply. A: A hypothesis

is base on knowledge and research. B: A hypothesis is an idea about the solution to a problem. C: A hypothesis is created after an experiment is completed. D: A hypothesis should make a claim about how two factors are related.
Chemistry
2 answers:
ruslelena [56]3 years ago
6 0
The answer is be because a hypothesis is just a educated guess or a theory
kkurt [141]3 years ago
5 0

Answer:

You're answer would be B.

Explanation:

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Calculate ΔHrxnΔHrxn for the following reaction: 3C(s)+4H2(g)→C3H8(l)3C(s)+4H2(g)→C3H8(l) Use the following reactions and given
mihalych1998 [28]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -120.9 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

3C(s)+4H_2(g)\rightarrow C_3H_8(l)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C_3H_8(l)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)    \Delta H_1=-2026.6kJ

(2) C(s)+O_2(g)\rightarrow CO_2(g)     \Delta H_2=-393.5kJ     ( × 3)

(3) 2H_2(g)+O_2(g)\rightarrow 2H_2O(g)     \Delta H_2=-483.5kJ     ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (-\Delta H_1)]+[3\times \Delta H_2]+[2\times \Delta H_3]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times -(-2026.6))+(3\times (-393.5))+(2\times (-483.5))]=-120.9kJ

Hence, the \Delta H^o_{rxn} for the reaction is -120.9 kJ.

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Dmitri Mendeleev Was the name of the guy you where looking for
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The equilibrium will shift to the left or the backward reaction since addition of <span>CH3COONa will add more CH3COO- ions to the solution. The formation of reactants are promoted.</span>
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