Answer:
The probability that exactly two have flaws is P (x=2) = 0.2376
Step-by-step explanation:
Here
Success= p= 0.15
Failure = q= 0.85
total number= n= 8
Number chosen = x= 2
Applying the binomial distribution
P (x=x) = nCx p^x(q)^n-x
P (x=2) = 8C2 0.15 ²(0.85)^8
P (x=2) = 0.2376
The success is chosen about which we want to find the probability. Here we want to find the probability that exactly two have flaws so success would be having flaws therefore p = 0.15
Answer:
The magazine that cost $15.24 for 6 issues cost more by $0.60/60 cents.
Step-by-step explanation:
Since $15.24 is 6 issues each and you need to even out the issues add $15.24+$15.24 then you would get $30.48, because its 15.24 each 6 add them both and it would be 12 issues. And the first issue $29.88 for 12 issues is only $29.88 while the other is $30.48 so the one with 6 issues/the second cost more than the first.
60 cents more because 29.88+60=30.48.
Answer:
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.0518
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
In this question:
. So
The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.
Answer: 1 1/3 or 4/3
Step-by-step explanation: f(4) =1/3(4) = 4/3 = 1 1/3
Plug 8 for y
8 = 2x + 4
Subtract 4
4 = 2x
Divide by 2
x = 2
Plug 16 for y
16 = 2x + 4
Subtract by 4
12 = 2x
Divide by 2
x = 6
Substitute 20 for y
20 = 2x + 4
16 = 2x
x = 8
Substitute 22 for y
22 = 2x + 4
18 = 2x
9 = x
So the values are 2, 6, 8, 9
