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babunello [35]
3 years ago
5

An empty bulldozer weighed 5 8/10 tons if it scooped up 7 1/10 tons of dirt, what would be the combined weight of the bulldozer

and dirt
Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

Answer:The combined weight of the bulldozer and dirt is 12 8/10 tons

Step-by-step explanation:

The weight of the empty bulldozer is 5 8/10 tons. We would simplify the weight of the bulldozer by converting 5 8/10 tons to improper fraction, it becomes (50 + 8)/10 = 58/10 tons.

It scooped up 7 1/10 tons of dirt. Converting the weight of the dirt to improper fraction, it becomes

(70 + 1)/10 = 70/10 tons

The combined weight of the bulldozer and dirt would be the weight of the bulldozer + the weight of the dirt. It becomes. It becomes

58/10 + 70/10 = (58 + 70)/10 =

128/10 = 12 8/10 tons

OlgaM077 [116]3 years ago
3 0

Answer:

12 9/10 tons

Step-by-step explanation:

The answer would be 12 9/10 tons. The only thing you are doing is adding them together.

Correct me ANYONE if I'm wrong.

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You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
Solve for x, given the perimeter = 40 cm.<br><br>2x+1+x+4<br>I need fast please help me
koban [17]
X= 11.66 continuing, because 3x+5=40 is the equation. in fraction form it would be 35/3
3 0
2 years ago
The graph of f(x)=3•2^x -3 is shown below. G(x) is a transformation of f(x). How would you write the equation for the function g
Bezzdna [24]

Answer:

C

Step-by-step explanation:

To find the appropriate equation, notice the red graph has shifted up about 6 units. This means that 3*2^x-3 which is shifted by -3 will move 6 up. -3+6= 3. This means the function will have +3. Only B and C are options. Now test a point. Notice the red function crosses the y-axis at about 5 or 6 when x=0.

g(x) = 2^x+3\\g(0) = 2^0+3\\g(0)=1+3\\g(0)=4

This function doesn't match.

f(0) = 3*2^0+3\\f(0) = 3*1+3\\f(0)=6

This function matches. Option C is correct.

3 0
3 years ago
Will mark as Brainlist
Semmy [17]

The answer :

4/5

Step-by-step explanation:

4x-5y=0  

subtract 4x on both the sides  

4x-4x-5y = 0-4x  

-5y = -4x

divide by -5 on both the sides  

-5y/-5 = -4x/-5

y =( 4/5 )x  

4 0
3 years ago
Why is this simplified by combining like terms <br> 3(4x+5) +2
Inga [223]
3(4x+5)+2
3•4x=12x
5•3=15+2=17
Answer= 12x + 17
3 0
3 years ago
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