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mina [271]
3 years ago
6

As a talented grad of CMPEN 270, your new job as a digital designer is to design a "greedy" vending machine that accepts only ni

ckels, dimes, and quarters. It is "greedy" because it does not give back any change! There is only one type of snack inside the vending machine which sells for 20 cents. To simplify the problem, assume only one coin is accepted at a time and generates the following inputs (XY) to the state machine. (USE T-Flip Flops ONLY)
Condition XY
No coins were put in the vending machine 00
One nickel was put in the vending machine 01
One dime was put in the vending machine 10
One quarter was put in the vending machine 11

Engineering
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

See explaination

Explanation:

In the below answer "Z" is the output. please kindly check attachment for further details.

When z=1 , the vending machine gives snacks

z=0 , the vending machine doesn't give snacks.

And z becomes 1( high) only when the machine gets 20 cents or more than 20 cents. Since the machine doesn't give change, after giving snacks it will restart from initial state A (where no coins were put).

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Annealing is a process by which steel is reheated and then cooled to make it less brittle. Consider the reheat stage for a 100-m
zvonat [6]

Answer:

T = 858.25 s

Explanation:

Given data:

Reheat stage for a 100-mm-thick steel plate ( 7830 kg/m3,  c 550 J/kg K, k 48 W/m K),

initial uniform temperature ( Ti ) = 200 c

Final temperature = 550 c

convection coefficient  = 250 w/m^2 k

products combustion temp = 800 c

calculate how long the plate should be left in the furnace ( to attain 550 c )

first calculate/determine the Fourier series Number ( Fo )

\frac{T_{0}-T_{x}  }{T_{1}-T_{x}  } = C_{1} e^{(-0.4888^{2}*Fo )}

= 0.4167 = 1.0396e^{-0.4888*Fo}

therefore Fo =  3.8264

Now determine how long the plate should be left in the furnace

Fo = (\frac{k}{pc_{p} } ) ( \frac{t}{(L/2)^2} )

k = 48

p = 7830

L = 0.1

Input the values into the relation and make t subject of the formula

hence t = 858.25 s

8 0
3 years ago
Regeneration can only increase the efficiency of a Brayton cycle when working fluid leaving the turbine is hotter than the worki
storchak [24]

Answer:

True, <em>Regeneration is the only process where increases the efficiency of a Brayton cycle when working fluid leaving the turbine is hotter than working fluid leaving the compressor</em>.

Option: A

<u>Explanation: </u>

To increase the efficiency of brayton cycle there are three ways which includes inter-cooling, reheating and regeneration. <em>Regeneration</em> technique <em>is used when a turbine exhaust fluids have higher temperature than the working fluid leaving the compressor of the turbine. </em>

<em>Thermal efficiency</em> of a turbine is increased as <em>the exhaust fluid having higher temperatures are used in heat exchanger where the fluids from the compressor enters and increases the temperature of the fluids leaving the compressor. </em>

6 0
3 years ago
Read 2 more answers
A 1000 W iron utilizes a resistance wire which is 20 inches long and has a diameter of 0.08 inches. Determine the rate of heat g
SSSSS [86.1K]

Answer:

The rate of heat generation in the wire per unit volume is 5.79×10^7 Btu/hrft^3

Heat flux is 9.67×10^7 Btu/hrft^2

Explanation:

Rate of heat generation = 1000 W = 1000/0.29307 = 3412.15 Btu/hr

Area (A) = πD^2/4

Diameter (D) = 0.08 inches = 0.08 in × 3.2808 ft/39.37 in = 0.0067 ft

A = 3.142×0.0067^2/4 = 3.53×10^-5 ft^2

Volume (V) = A × Length

L = 20 inches = 20 in × 3.2808 ft/39.37 in = 1.67 ft

V = 3.53×10^-5 × 1.67 = 5.8951×10^-5 ft^3

Rate of heat generation in the wire per unit volume = 3412.15 Btu/hr ÷ 5.8951×10^-5 ft^3 = 5.79×10^7 Btu/hrft^3

Heat flux = 3412.15 Btu/hr ÷ 3.53×10^-5 ft^2 = 9.67×10^7 Btu/hrft^2

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3 years ago
Explain how use of EGR is effective in reducing NOx emissions 4. In most locations throughout the U.S., the octane number of reg
TiliK225 [7]

Answer:please see attached file

Explanation:

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4 years ago
The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a?
Zepler [3.9K]

The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a Valve/trap.

<h3>What is vapor?</h3>
  • In physics, a substance in the gas phase at a temperature lower than its critical temperature is referred to as a vapor or vapor.
  • This means that the vapor can be condensed to a liquid by increasing the pressure on it without decreasing the temperature.
  • An aerosol is distinct from a vapor.
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<h3>Why does vapor form?</h3>
  • Evaporation or sublimation are two processes that can be used to create it.
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  • In the atmosphere, water vapor frequently exists below the boiling point.

Learn more about vapor here:

brainly.com/question/14578189

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