Question

A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and that its average natural dry density is 82 pcf. This soil is to be placed in a compacted fill with a dry density specified at 96 pcf. How many cubic yards of borrow will be required to produce 50,000 yd3 of fill? What is the shrinkage factor for the borrow?

Answer 1

Answer:

shrinkage ratio  = 1.538

Explanation:

given data

water content = 22 %

dry density γ = 82 pcf

required dry density specified γ' = 96 pcf

required to produce = 50,000 yd³  = 50000 × 27 = 1350,000 ft³

solution

we get here first volume of borrow pit that is we know that

dry density ∝  $\frac{1}{volume}$  

so $\frac{\gamma d}{\gamma 'd} = \frac{v'}{v}$

$\frac{82}{96} = \frac{1350000}{v}$

v = 1580487.8 ft³

v = 58536.58 yd³

so here

shrinkage ratio will be as

shrinkage ratio = $\frac{96}{62.4}$  

shrinkage ratio  = 1.538