A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and
1 answer:
Answer:
shrinkage ratio = 1.538
Explanation:
given data
water content = 22 %
dry density γ = 82 pcf
required dry density specified γ' = 96 pcf
required to produce = 50,000 yd³ = 50000 × 27 = 1350,000 ft³
solution
we get here first volume of borrow pit that is we know that
dry density ∝
so
v = 1580487.8 ft³
v = 58536.58 yd³
so here
shrinkage ratio will be as
shrinkage ratio =
shrinkage ratio = 1.538
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Answer:
the percent increase in the velocity of air is 25.65%
Explanation:
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The first thing we must consider to solve this problem is the continuity equation that states that the amount of mass flow that enters a system is the same as what should come out.
m1=m2
Now remember that mass flow is given by the product of density, cross-sectional area and velocity
(α1)(V1)(A1)=(α2)(V2)(A2)
where
α=density
V=velocity
A=area
Now we can assume that the input and output areas are equal
(α1)(V1)=(α2)(V2)
Now we can use the equation that defines the percentage of increase, in this case for speed
Now we use the equation obtained in the previous step, and replace values
the percent increase in the velocity of air is 25.65%
Answer:
Rate of heat transfer to the room air per meter of pipe length equals 521.99 W/m
Explanation:
Since it is given that the radiation losses from the pipe are negligible thus the only mode of heat transfer will be by convection.
We know that heat transfer by convection is given by
where,
h = heat transfer coefficient = 10.45 (free convection in air)
A = Surface Area of the pipe
Applying the given values in the above formula we get