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Tomtit [17]
3 years ago
12

Which option should the engineers focus on as they develop the train in the following scenario?

Engineering
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

  Engineers can design a train with a regenerative braking system

Explanation:

Assuming the point of the question is that the engineers want to focus on using energy efficiently when starting and stopping, they would likely want to consider a regenerative braking system. Such a system can store energy during braking so that it can be used during starting, reducing the amount of energy that must be supplied by an outside power source.

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I need answer to this question
blagie [28]

Answer:

1. Graph C

2. Friction

Explanation:

1. The line on all of the graphs shown represents velocity. The formula for velocity is v=\frac{d}{t} where d is distance and t is time. Focusing on the first lap, the starting point on the graph should be the origin and the "ending" point should be (20, 3). These requirements eliminate graph A as an answer because its "end" is not (20, 3). During the break, the student does not move, so the slope of the line should be completely horizontal. The break lasted for 5 minutes, so the correct graph should have a horizontal line between the points (20, 3) and (25, 3). This requirement eliminates graph B and D because their break is either not long enough (B) or too long (D).

2. Friction slows down the movement of objects. When an object is rough, it produces more friction which causes the object to be slowed more. When an object is smooth, friction slows it less than it would for a rough object.

6 0
3 years ago
The following true stresses produce the corresponding true plastic strains for a brass alloy: True Stress (psi) True Strain 4840
Assoli18 [71]

Answer:

70,900

Explanation:

Given :

True stress (psi) _____ True strain (psi)

48400 ______________ 0.11

60400 ______________ 0.19

Using ratio simplification :

Let :

s = True stress ; t = true strain

s1 = 48400

s2 = 60400

t1 = 0.11

t2 = 0.19

True stress, s0 ; needed to produce a True plastic strain, tp = 0.26

(s0 - s1) / (s2 - s1) = (tp - t1) / (t2 - t1)

(s0 - 48400)/(60400 - 48400) = (0.26 - 0.11)/(0.19 - 0.11)

(s0 - 48400)/12000 = 0.15/0.08

Cross multiply :

0.08(s0 - 48400) = 0.15 * 12000

0.08s0 - 3872 = 1800

0.08s0 = 1800 + 3872

0.08s0 = 5672

s0 = 5762 / 0.08

s0 = 70,900

The true stress required to produce a true plastic strain of 0.26 is 70,900

5 0
3 years ago
Stefan Lano needs displays that will show the musical instrument inventory in his chain of music stores that caters to musicians
AlexFokin [52]

Answer:

attached below is an example of  the form

Explanation:

This type of form-fill can be described/developed based on the requirements or information needed by the organization in order to perfectly fulfill an order  and also to retain customers by making the form very easy and interactive attached below is an example of such form fill  interface

4 0
3 years ago
Cos square there + cos square theta multiply cot square theta = cot square theta​
Ivahew [28]

Explanation:

We need to prove that : \cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta=\cot^2\theta

Taking LHS : \cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta

Taking \cos^2\theta common as follows :

\cos^2\theta(1+ \cot^2\theta) ...(1)

We know that :

cosec^2\theta-\cot^2\theta=1\\\\cosec^2\theta=1+\cos^2\theta ....(2)

Use equation (2) in equation (1) as follows :

\cos^2\theta{\cdot} cosec^2\theta

We know that : cosec\theta=\dfrac{1}{\sin\theta}

So,

\cos^2\theta{\cdot} \dfrac{1}{\sin^2\theta}\\\\=\cot^2\theta

=RHS

Hence, LHS = RHS

8 0
3 years ago
Which of these are ways to protect yourself from electrical hazards?
shtirl [24]

Answer:

Understand how a GFCI can protect you and Use tools and power cords safely. I do believe

Explanation:

5 0
4 years ago
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