1.25, because change the fractions into decimals and then add it from there so it would be add like, 0.75+0.5=1.25
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Answer:
the required diameter is 0.344 m
Explanation:
given data:
flow is laminar
flow of carbon dioxide Q = 0.005 Kg/s
for flow to be laminar, Reynold's number must be less than 2300 for pipe flow and it is given as
arrange above equation for diameter
\frac{\rho Q D}{\mu A }<2300
dynamic density of carbon dioxide = 1.47× Pa sec
density of carbon dioxide is 1.83 kg/m³
D = 0.344 m
Answer:
D
Explanation:
the sponge's and rags are meant for this exact purpose
Answer:
a) 15.37 mm
b)
c) 5.7186 W/m². K
d) 0.60 m
Explanation:
Given that :
The surface temperature = 130°C = ( 130+ 273 ) K = 473 K
suspended in quiescent air at 25°C = ( 25 + 273 ) K = 298 K
Atmospheric Pressure = 1 atm
The properties obtained from Table A - 4 include :
v =
k = 0.03 W/m K
Pr = 0.700
η = 5
Hence, the boundary layer thickness at a location 0.15 m measured from the lower edge is 15.37 mm
b) The maximum velocity in the boundary layer with f'(n) = 0.275
u = 0.3659 m/s
the maximum velocity in the boundary layer at this location is 0.3659 m/s
the position in the boundary layer where the maximum occur is calculated as:
3.074 mm
c) Using the similarity solution result, , determine the heat transfer coefficient 0.15 m from the lower edge.
we know that:
=
= 28.593
Making the subject from the above formula:
= 5.7186 W/m². K
d) to determine the location on the plate that the boundary layer we become turbulent ; we have the following:
0.60 m