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3 years ago

PLEASE HELP 100 POINTS!!! WILL MARK BRAINLIEST

Engineering

2 answers:

OlgaM077 [116]3 years ago

5 0

Business plan, a good strategy to help pin point the house best fetchers

Hatshy [7]3 years ago

4 0

Answer:

Explanation:

Jake is a freelance architect so he is not good at creating a business plan. But he should be good at drawings and math. As analyzing bids require comparing numbers side by side, Jake can help the real estate firm to create a <u>spreadsheet</u>.

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TP-6 What should you do when fueling an outboard boat with a portable tank?

nikklg [1K]

Portable is the same one u only knew

4 0

3 years ago

Technician A says that when using an impact wrench to remove a bolt from the front of an engine's crankshaft, the crankshaft mus

Lady bird [3.3K]

Answer:

d. Neither A nor B

Explanation:

Mostly for exhaust bolts we use impact wrenches. Impact wrenches are very useful on flywheels because the crank shaft needs to be fixed from rotating. Also impact wrenches are useful on cars for loosening wheel nuts. The wheels need not to be restrained or the brakes need not to be applied to fiz wheels in position.

3 0

3 years ago

Air enters a compressor operating at steady state with pressure of 90 kPa, at a temperature of 350 K, and a volumetric flow rate

natita [175]

Answer:

$T_{out} = 457.921\,K$

Explanation:

Before determining the exit temperature of air, it is required to find the specific enthalpy at outlet by using the First Law of Thermodynamics:

$-\dot Q_{out} + \dot W_{un} + \dot m \cdot (h_{in}-h_{out})=0$

$h_{out} = \frac{\dot W_{in}}{\dot m}- q_{out} +h_{in}$

An ideal gas observes the following mathematical model:

$P\cdot V = n\cdot R_{u}\cdot T$

Where:

$P$ - Absolute pressure, in kilopascals.

$V$ - Volume, in cubic meters.

$n$ - Quantity of moles, in kilomole.

$R_{u}$ - Ideal gas universal constant, in $\frac{kPa\cdot m^{3}}{kmole\cdot K}$ .

$T$ - Absolute temperature, in kelvin.

The previous equation is re-arranged in order to calculate specific volume at inlet:

$P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T$

$\nu = \frac{R_{u}\cdot T}{P\cdot M}$

$\nu_{in} = \frac{(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} )\cdot (350\,K)}{(90\,kPa)\cdot (28.97\,\frac{kg}{kmol} )}$

$\nu_{in} = 1.116\,\frac{m^{3}}{kg}$

The mass flow is:

$\dot m = \frac{\dot V}{\nu_{in}}$

$\dot m = \frac{0.6\,\frac{m^{3}}{s} }{1.116\,\frac{m^{3}}{kg} }$

$\dot m = 0.538\,\frac{kg}{s}$

The specific enthalpy in ideal gases depends on temperature exclusively. Then:

$h_{in} = 350.49\,\frac{kJ}{kg}$

The specific enthalpy at outlet is:

$h_{out} = \frac{75\,kW}{0.538\,\frac{kg}{s} }-30\,\frac{kJ}{kg} + 350.49\,\frac{kJ}{kg}$

$h_{out} = 459.895\,\frac{kJ}{kg}$

The exit temperature of air is:

$T_{out} = 457.921\,K$

5 0

3 years ago

What is the steady-state value of the output of a system with transfer function G(s)= 6/(12s+3), subject to a unit-step input?

fenix001 [56]

Answer:

At steady state output will be 2

Explanation:

We have given transfer function $G(S)=\frac{6}{12S+3}$

Input is unit step so $X(S)=\frac{1}{S}$

We know that $G(S)=\frac{Y(S)}{X(S)}$ , here $Y(S)$ , is output

So output $Y(S)=G(S)\times X(S)$

$Y(S)=\frac{1}{S}\times \frac{6}{12S+3}$

Taking 12 common from denominator

$Y(S)=\frac{1}{2S(S+\frac{1}{4})}$

Now using partial fraction

$\frac{1}{2S(S+\frac{1}{4})}=\frac{A}{2S}+\frac{B}{(S+\frac{1}{4})}$

$\frac{1}{2S(S+\frac{1}{4})}=\frac{A(S+\frac{1}{4}+2BS)}{2S(S+\frac{1}{4})}$

$AS+\frac{A}{4}+2BS=1$

On comparing coefficient A=4 and B = -2

Putting the values of A and B in Y(S)

$Y(S)=\frac{4}{2S}-\frac{2}{S+\frac{1}{4}}$

Now taking inverse la place

$y(t)=2-2e^{\frac{-t}{4}}$

Steady state means t tends to infinite

So output at steady state = $y(t)=2-2e^{\frac{-\infty}{4}}$

$y(t)=2-0=2$

3 0

2 years ago

State 3 advantages and 3 disadvantages of unit rate contract

Zinaida [17]

6 would be the answer

7 0

3 years ago