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You toss an apple across the room to a friend. Which of the following

Tcecarenko [31]

Answer:

At top vertical componant of velocity is zero

6 0

4 years ago

The ms = 0.5645 and mk=0.1113 for a 30 N box on level ground. What level force is needed to start the box moving

nevsk [136]

Answer:

16.935 N

Explanation:

In order to make the box start moving, the level force applied on the box (F) must be greater than the force of static friction that keeps the box at rest, which is equal to

$F_f = \mu_s (mg)$

where

$\mu_s = 0.5645$ is the coefficient of static friction

(mg) = 30 N is the weight of the box

Therefore, the condition for F must be:

$F \geq F_f\\F \geq \mu_k (mg)=(0.5645)(30 N)=16.935 N$

So, the applied force must be greater than this value.

3 0

4 years ago

A uniform electric field (constant in magnitude and direction) exists in the region between two oppositely charged plane paralle

Over [174]

Answer:

Part a)

$E = 39.7 N/C$

Part b)

$v_f = 1.10\times 10^4 m/s$

Explanation:

Part a)

Proton is released from one plate and strike at other plate in time

$t = 2.90 \times 10^{-6} s$

$d = 1.60 cm$

now we will have

$d = \frac{1}{2}at^2$

$0.0160 = \frac{1}{2}a(2.90 \times 10^{-6})^2$

$a = 3.8 \times 10^9 m/s^2$

now we know that

$a = \frac{qE}{m}$

$3.8 \times 10^9 = \frac{(1.6 \times 10^{-19})E}{(1.67 \times 10^{-27})}$

$E = 39.7 N/C$

Part b)

Speed of the proton when it strike the other plate can be calculated by kinematics equations

$v_f^2 - v_i^2 = 2ad$

$v_f^2 - 0 = 2(3.8 \times 10^9)(0.0160)$

$v_f = 1.10\times 10^4 m/s$

4 0

4 years ago

A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground

forsale [732]

Answer:

14.68m/s

Explanation:

As per the question, the data provided is as follows

Mass = M = 0.148 kg

Height = h = 11 m

Initial velocity = U = 0 m/s

Final velocity = V

Gravitational force = F

Mass = M

Based on the above information, the speed that hit to the ground is

As we know that

Work to be done = Change in kinetic energy

$F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )$

$M g h = (\frac{1}{2} ) M ( V^2 - U^2 )$

$g h = (\frac{1}{2} ) ( V^2 - U^2 )$

$V^2 - U^2 = 2gh$

$V^2 - 0 = 2gh$

$V = \sqrt{2 g h}$

$= \sqrt{2\times9.8\times11}$

= 14.68m/s

7 0

3 years ago

In a circuit a battery is used to

jeyben [28]

The power of batteries in a circuit. The key functions of a battery and bulb in a circuit are explained. A battery is a source of energy which provides a push - a voltage - of energy to get the current flowing in a circuit. A bulb uses the electrical energy provided by the battery, but does not use current.

HOPE IT HELPS YOU OUT!

8 0

4 years ago

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