Answer: Option (C) is the correct answer.
Explanation:
Whether an acid is weak or strong it will cause harm if it comes in direct contact with the skin, eyes or mouth etc.
Thus, in order to prevent oneself, it is advised to wear a lab coat while working in laboratory as acids break down fabrics and can cause burns if the acids are strong.
Hence, a lab coat acts as a protective layer on the clothes so that even if acid falls on it then it might not reach the skin immediately and on time prevention can be taken.
Explanation:
let's assume that:
v1= 600ml=0,6l
T1=27°C= 300K
p1=700mmHG=93326Pa
T2=-20°C=253K
p2=500mmHg=66661
V2=?
p1V1/T1=p2V2/T2 => V2=p1V1T2/p2
V2= 93326*0,6*253/66661
V2=212,52l
Answer:
C 350W
Explanation:
Given power output to walk on a flat ground to be 300W, h = 0.05x, v = 1.4m/s
m = 70kg and g =9.8m/s².
x = horizontal distance covered
Total energy used = potential energy used in climbing and the energy used in a walking the horizontal distance.
E = mgh + 300t
Where t is the time taken to cover the distance
x = vt and h = 0.05vt
So
E = mg×0.05×vt + 300t
Substituting respective values
E = 70×9.8×0.05×1.4t +300t = 348t
P = E/t = 348W ≈ 350W.
