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scoundrel [369]
3 years ago
5

The fastest speed ever measured for a tennis ball served by a player was 263 km/h. The distance of the tennis court from one end

to the other is 23.8 m. (a) How long does the tennis ball take to go from one end of the court to the other? (b) Suppose that the time the tennis ball takes to go from one end of the court to the other is 0.6 s. What is the speed of the tennis ball?
Physics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

0.3257 seconds

39.67 m/s

Explanation:

Speed = 263 km/h

Converting to m/s

1\ km/h=\frac{1}{3.6}\ m/s

263\ km/h=263\times \frac{1}{3.6}\ m/s=\frac{1315}{18}\ m/s

Distance to travel = 23.8 m

Time = Distance / Speed

Time=\frac{23.8}{\frac{1315}{18}}=0.3257\ s

The time taken to go from one end of the court to the other is 0.3257 seconds

Time = 0.6 s

Speed = Distance / Time

Speed=\frac{23.8}{0.6}=39.67\ m/s

The speed of the tennis ball is 39.67 m/s

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3 years ago
Which expression correctly describes energy using SI units
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Answer:

Joule

Explanation:

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m2·kg·s-2

5 0
2 years ago
A 75kg man climbs the stairs to the fifth floor of a building. A total hieght of 16m. His potential energy has increased by
yKpoI14uk [10]

Answer:

11760 joules

Explanation:

Given

Mass (m) = 75kg

Height (h) = 16m

Required

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This is calculated as thus:

PE = mgh

Where g = 9.8m/s²

Substitute values for m, g and h.

P.E = 75 * 9.8 * 16

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8 0
3 years ago
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
Delvig [45]

Answer:

The resistance must be 6.67\Omega

Solution:

Resistance, R_{1} = 20\Omega

Resistance, R_{2} = 10\Omega

For the current to be the same when the switch is open or closed, the resistances must be connected in parallel as current is distributed in parallel with the same voltage across the circuit:

Thus in parallel:

\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

\frac{1}{R_{eq}} = \frac{1}{20} + \frac{1}{10}

R_{eq} = 6.67\ \Omega

4 0
3 years ago
A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa
Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute =W_B=10 g

Given mass of solvent=W_A=90 g

k_f=1.86^{\circ}C/m

Freezing point of solution =-3.33^{\circ}C

Freezing point of solvent =0^{\circ}C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33=3.33^{\circ}

\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}

M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}

M_B=62.06 g/mol

Hence, molar mass of unknown liquid is 62.06g/mol.

6 0
2 years ago
Read 2 more answers
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