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scoundrel [369]
3 years ago
5

The fastest speed ever measured for a tennis ball served by a player was 263 km/h. The distance of the tennis court from one end

to the other is 23.8 m. (a) How long does the tennis ball take to go from one end of the court to the other? (b) Suppose that the time the tennis ball takes to go from one end of the court to the other is 0.6 s. What is the speed of the tennis ball?
Physics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

0.3257 seconds

39.67 m/s

Explanation:

Speed = 263 km/h

Converting to m/s

1\ km/h=\frac{1}{3.6}\ m/s

263\ km/h=263\times \frac{1}{3.6}\ m/s=\frac{1315}{18}\ m/s

Distance to travel = 23.8 m

Time = Distance / Speed

Time=\frac{23.8}{\frac{1315}{18}}=0.3257\ s

The time taken to go from one end of the court to the other is 0.3257 seconds

Time = 0.6 s

Speed = Distance / Time

Speed=\frac{23.8}{0.6}=39.67\ m/s

The speed of the tennis ball is 39.67 m/s

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Nookie1986 [14]

Answer:

Sedimentary rocks are usually formed under water when grains of broken rocks are glued together while igneous rocks form when melted rock (magma or lava) cools and metamorphic are rocks that once were igneous or sedimentary rocks but have been changed by pressure and temperature.

4 0
3 years ago
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The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a
emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\  I_2= 0.125 \ foot-candles

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

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6 0
2 years ago
A particle is moving with SHM of period pie . initially it is 10 cm from The center of the motion and moving in the positive dir
Viefleur [7K]

Answer:

y = 10.44cos(2t - 0.291) cm

Explanation:

y = Acos(2πt/T + φ) = Acos(2πt/π + φ) = Acos(2t + φ)

v = y' = -2Αsin(2t + φ)

10 = Acos(2(0) + φ) = Acosφ

6 = -2Αsin(2(0) + φ) = -2Asinφ

6/10 = -2Asinφ/Acosφ = -2tanφ

tanφ = -0.3

φ = -0.291 radians

10 = Acos(-0.291)

A = 10/cos(-0.291) = 10.44

7 0
3 years ago
An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev/min to 200 rev/min in 4.00 s.
Veseljchak [2.6K]

Answer:

a) -1.25 rev/s² and 23.3 rev

b)  2.67s

Explanation:

a) ωФ_o_z = (500 rev/min)(1min/ 60s) => 8.333 rev/s

ωФ_Z= (200 rev/min)(1min/ 60s) => 3.333rev/s

time 't'= 4 s

angular acceleration 'αФ_Z'=?

constant angular acceleration equation is given by,

ωФ_Z= ωФ_o_z + αФ_Zt

αФ_Z= (ωФ_Z - ωФ_o_z )/t => (3.333-8.333)/4

αФ_Z= -1.25 rev/s²

θ-θФ_o = ωФ_o_z t + 1/2αФ_Zt²

      =(8.333)(4) + 1/2 (-1.25)(4)²

      =23.3 rev

b) ωФ_Z=0   (comes to rest)

ωФ_o_z = 3.333 rev/s

αФ_Z= -1.25 rev/s²

ωФ_Z= ωФ_o_z + αФ_Zt

t= (ωФ_Z - ωФ_o_z)/αФ_Z => (0- 3.333)/-1.25

t= 2.67s

3 0
3 years ago
Calculate the pH of hydronium ions in a 0.000 01 M solution of the strong acid HI.
enyata [817]
<h3>Answer:</h3>

pH = 5

<h3>Explanation:</h3>

<u>We are given;</u>

  • Concentration of a solution HI as 0.00001 M

We are required to calculate the pH of Hydronium ions.

  • When the acid dissociates in water to;

HI + H₂O → H₃O⁺(aq) + I⁻(aq)

  • Therefore;
  • The concentration of H₃O⁺ ions is 0.00001 M\
  • We need to know that pH = -log[H₃O⁺]

Therefore;

pH =-log 0.00001 M

     = 5

Thus, the pH of the hydronium ions is 5

7 0
3 years ago
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