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4 years ago

How many moles of nitrogen would react with excess hydrogen to produce 520 mL of ammonia?

Chemistry

1 answer:

lapo4ka [179]4 years ago

6 0

N₂ + 3H₂ = 2NH₃

n(N₂)=V(NH₃)/{2Vm}

V(NH₃)=520 mL=0.520L
Vm=22.4 L/mol

n(N₂)=0.520/{2*22.4}=0.0116 mol

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First we have to calculate the mass defect $(\Delta m)$ .

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The energy released for 230 grams of decay of thorium is $2.0916\times 10^{-13}J$

We need to calculate the energy released for the decay of 3 grams of thorium. By applying unitary method, we get:

As, 230 grams of Th release energy of = $2.0916\times 10^{-13}J$

Then, 3 grams of Th will release energy of = $\frac{2.0916\times 10^{-13}}{230}\times 3=2.728\times 10^{-15}J$

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