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Alborosie
4 years ago
14

Seashells can be most easily separated from sand because of differences in which property?density

Chemistry
2 answers:
Zolol [24]4 years ago
4 0

Answer: particle size

Explanation:

1. Density is defined as mass contained per unit volume.

If two substances have different densities, the one with higher density sinks in the one with lower density.

2. Magnetism is the property of an object that can attract or repel objects that have a magnetic material like iron inside them.

It is used in separation when one of the material is magnetic.

3. Boiling point is the temperature when liquid converts to gaseous form.

It is used to separate two liquids with different boiling points using distillation.

4. Particle size is used to separate two solids with different sizes. Sand particles are smaller than seashells and thus can be separated using sieve.

Artyom0805 [142]4 years ago
3 0
The answer is D, particle size
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Answer:

Groups show similar chemical properties about the elements

Explanation:

The periodic table is divided into groups and periods. Groups are vertical while periods are horizontal.

All elements in the same group possess the same number of outermost shell electrons. This number of outermost shell electrons controls the reactivity of the elements in the group.

Hence, groups show similar chemical properties of the elements in them, Groups separate elements into families which assist in the speedy study of elements.

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4 years ago
47.9 ml hrdrogen is collected at 26° Celsius and 718 torr. Find the volume occupied at STP
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Answer:

41.45 mL

Explanation:

Applying the general gas equation,

PV/T = P'V'/T'............... Equation 1

Where P = Initial pressure of hydrogen, V = Initial volume of hydrogen, T= Initial Temperature of hydrogen, P' = Final pressure of hydrogen, V' = Final Volume of Hydrogen, T' = Final Temperature.

make V' the subject of the equation

V' = PVT'/TP'................ Equation 2

Given: P = 718 torr = (718×133.322) N/m² = 95725.196 N/m², V = 47.9 mL = 0.0479 dm³, T = 26 °C = (26+273) = 299 K, T' = 273 K, P' = 101000 N/m²

Substitute these values into equation 2

V' = ( 95725.196×0.0479×273)/(299×101000)

V' = 0.04145 dm³

V' = 41.45 mL

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