6 sodium and 6 Bromine in 6NaBr
Explanation:
The two half equations are;
3e + HNO3 → NO
S→ H2SO4 + 6e
When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.
<em>Which factor will you use for the top equation?</em>
We multiply by 2 to make the number of electrons = 6e
<em>Which factor will you use for the bottom equation?</em>
We multiply by 1 to make the number of electrons = 6e
Answer:
The reagents are
.
Explanation:
1-Methylenecyclopentene is treated with HBr form 1-bromo-1-methylcyclopentane, which is treated with strong base ethoxide ion and forms 1-methylcyclopent-1-ene.
This alkene is treated with osmium tetraoxide in the presence of sodium bisulfite to form target product.
The chemical reaction is as follows.
Answer : The correct option is, (2) Energy is absorbed as bonds are broken.
Explanation :
As we know that the bonds are formed and breaks during the chemical reaction. Some energy is released or absorbed when the bonds are formed and breaks during the chemical reaction.
During the bond breaking, some energy is required to break the bonds.
During the bond formation, some energy is released to the formation of the bonds.
In the given reaction, the bond between the hydrogen-hydrogen in
are breaking into two hydrogen. That means during the bond breaking, some energy is required or absorbed to break the bonds.
Hence, the correct option is, (2) Energy is absorbed as bonds are broken.