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2 years ago

Can someone help me out or tell me if I’m right or wrong on both problems !

Mathematics

1 answer:

butalik [34]2 years ago

5 0

They seem correct. For the first one you don’t really need the 1, so you could write it as y=-x+2, but both ways work

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What is 713.49 written in standard form

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It’s Seven Hundred Thirteen point forty-nine

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Licemer1 [7]

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Is there a 62.5 miles option?

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2 years ago

Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many poss

egoroff_w [7]

Answer:

4 possible outcomes

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

In this problem

The probability of choose a blue card is

$x=7$

$y=7+4+6+8=25$

substitute

$P=\frac{7}{25}$

The probability of choose a green card is

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$y=7+4+6+8=25$

substitute

$P=\frac{4}{25}$

The probability of choose a red card is

$x=6$

$y=7+4+6+8=25$

substitute

$P=\frac{6}{25}$

The probability of choose a yellow card is

$x=8$

$y=7+4+6+8=25$

substitute

$P=\frac{8}{25}$

The sum of the probabilities of the 4 possible outcomes is equal to

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3 years ago

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castortr0y [4]

1/6

Sorry if this is wrong!!

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3 years ago

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