Chemical reactions convert reactants to products, whose properties differ
from those of the reactants. Chemical equations are a compact and
convenient way to represent chemical reactions. They have the general form
Reactant(s) → Product(s)
The arrow in the equation means "changes to" or
"forms." The reaction of gaseous nitrogen with hydrogen to
produce ammonia, NH
3
, is represented by the chemical equation
Although there are thousands of chemical reactions, a significant number
of them, especially those that are not organic reactions, can be
classified according to four general patterns: combination, decomposition,
displacement, and exchange.
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The atomic mass of an element is the number of times of an atom of that element is heavier than an atom of carbon taken as 12. In simpler way, atomic mass is number of protons present in nucleus of an atom, which is a characteristic of an chemical element and is determines place of the element in the periodic table. Mass number is total number of protons and neutrons. If an uncharged atom looses electron from its outermost shell, it becomes cation, which is positively charged species. Atomic number and mass number do not change if electron goes out of an atom.
Uncharged copper after loosing two electrons is converted to
which can be represented as follows:
→
Answer:
Mass is conserverd
Explanation:
Any chemical reaction must follow the law of conservation of mass. Meaning that mass cannot be created nor destroyed. Since all chemical reactions must follow this law, no matter what reaction happens, mass is conserved.
Energy is the main cause of global conversation currents
For the given molecule, we are asked to give-
- The electron configuration of an isolated B atom
- The electron configuration of an isolated F atom
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
- valence orbitals, if any, remain unhybridized on the B atom.
- The electron configuration of an isolated B atom:
as atomic number of B is 5
electronic configuration will be [He] 2s² 2p¹
- The electron configuration of an isolated F atom:
as atomic number of F is 9
electronic configuration will be [He] 2s² 2p5
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.
as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.
- valence orbitals, if any, remain unhybridized on the B atom will be 1
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