Answer:
Filtration
Explanation:
Filtration is a physical separation technique that is used to separate solids from liquids or gases. The process involves the use of a filter which allows just the liquid to pass through.
In this case, the coffee beans is the solid and the boiling water is the liquid. The special piece of paper is the medium (filter) through which the coffee is collected.
The coffee coming through the special piece of paper (filter) is called a filtrate.
Filtration is used in the preparation of the cup of coffee.
Answer: Animals and Humans or groundwater
Explanation: If animals and humans are moving around a lot and the human is using machinery, it will cause physical erosion. Ground water may be because that is the only water it may have to erode
A short circuit is an easier path for electron flow
Equilibrium constant for the reaction CaCl₂.2H₂O (s) <-------> CaCl₂ (s) + H₂O (g) is [H₂O]².
Equilibrium constant is a temperature dependent constant which does not depend on the concentration of reactant or product.
The reaction given is:
CaCl₂.2H₂O (s) <-------> CaCl₂ (s) + H₂O (g)
The equilibrium constant for the given reaction is given by:
Keq = [H₂O]² [CaCl₂] / [CaCl₂.2H₂O]
Since, we know that the concentration of a solid remain unity.
Hence, [CaCl₂] = 1
[CaCl₂.2H₂O] = 1
So, the equilibrium constant becomes,
Keq = [H₂O]²
Hence, Equilibrium constant for the reaction CaCl₂.2H₂O (s) <-------> CaCl₂ (s) + H₂O (g) is [H₂O]²
Learn more about Equilibrium constant here, brainly.com/question/10038290
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Answer:
0.804g of NaHCO₃ you must add
Explanation:
pKa of HCO₃⁻/CO₃²⁻ is 10.32.
It is possible to find pH of a buffer by using H-H equation, thus:
pH = pka + log [A⁻] / [HA]
<em>Where [HA] is concentration of acid (HCO₃⁻) and [A⁻] is concentration of conjugate acid (CO₃²⁻).</em>
Moles of CO₃²⁻ = K₂CO₃ are:
4.00g ₓ (1mol / 138.206g) = 0.0289 moles CO₃²⁻
Replacing:
10.80 = 10.32 + log [0.0289] / [HCO₃⁻]
[HCO₃⁻] = 0.009570 moles you need to add to obtain the desire pH
As molar mass of NaHCO₃ is 84.007g/mol, mass of NaHCO₃ is:
0.009570 moles ₓ (84.007g / mol) =
<h3>0.804g of NaHCO₃ you must add</h3>
