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3 years ago

Round 38.86 to one decimal place

2 answers:

6 0

If you round to one decimal place it would be 38.9 because the last number is a biger number that 5 and that makes the number in front go up one number

statuscvo [17]3 years ago

4 0

38.9
Hope this helped :)

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Solve. 2x + 8y = 18 y= -x + 6 Enter your answer, in the form (x, y), in the boxes.

iren2701 [21]

Answer:

it is a simultaneous equation and I used Elimination method

$2x + 8y = 18(equ \: 1) \\ y = - x + 6 \: \\ y + x = 6 \: (equ \: 2) \\ \\ from \:( equ2) \\ \: x = 6 - y \: (equ \: 3 )\\ sub. \: (equ3) \: in \: (equ2) \\ 2(6 - y )+ 8y = 18 \\ 12 - 2y + 8y = 18 \\ 6y = 18 - 12 \\ 6y = 6 \\ \frac{6y}{6} = \frac{6}{6} \\ y = 1 \\ \\ sub. \: y \: in \: equ3 \\ x = 6 - y \\ x = 6 - 1 \\ x = 5 \\ \\ \\ y = 1 \: \: x = 5$

5 0

3 years ago

I need an explanation on how to work this out

rjkz [21]

Answer:

make 360×each number given/15 students to start drawing

360×7/15=168°

360×5/15=120°

360×2/15=48°

360×1/15=24°

now draw each one from the radius give to the clockwise

if you don't know what's clockwise direction, see it from your house or tell anybody in your home to tell you where is clockwise

after you finish drawing, label each section by writing the names on the correct sections ( you can write in or out of the circle)

6 0

3 years ago

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - α)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of t for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$