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murzikaleks [220]
3 years ago
8

Round 38.86 to one decimal place

Mathematics
2 answers:
enyata [817]3 years ago
6 0
If you round to one decimal place it would be 38.9 because the last number is a biger number that 5 and that makes the number in front go up one number
statuscvo [17]3 years ago
4 0
38.9 
Hope this helped :)
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Solve.<br>2x + 8y = 18<br>y= -x + 6<br>Enter your answer, in the form (x, y), in the boxes.​
iren2701 [21]

Answer:

it is a simultaneous equation and I used Elimination method

2x + 8y = 18(equ \: 1) \\   y =  - x + 6 \:  \\ y + x = 6 \: (equ \: 2) \\  \\ from \:( equ2) \\  \:  x = 6 - y \: (equ \: 3 )\\ sub. \: (equ3) \: in \: (equ2) \\ 2(6 - y )+ 8y = 18 \\ 12 - 2y + 8y = 18 \\ 6y = 18 - 12 \\ 6y = 6 \\  \frac{6y}{6}  =  \frac{6}{6}   \\  y = 1 \\  \\ sub. \: y \: in \: equ3 \\ x = 6 - y \\ x = 6 - 1 \\ x = 5 \\  \\  \\ y = 1 \:  \: x = 5

5 0
3 years ago
I need an explanation on how to work this out
rjkz [21]

Answer:

make 360×each number given/15 students to start drawing

360×7/15=168°

360×5/15=120°

360×2/15=48°

360×1/15=24°

now draw each one from the radius give to the clockwise

if you don't know what's clockwise direction, see it from your house or tell anybody in your home to tell you where is clockwise

after you finish drawing, label each section by writing the names on the correct sections ( you can write in or out of the circle)

6 0
3 years ago
Ten college students were randomly selected. Their grade point averages​ (GPAs) when they entered the program were between 3.5 a
solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
3 years ago
YALL NEVER ANSWER AH POOP plz help
lakkis [162]

Answer:

The given point A (6,13) lies on the equation.  True

The given point  B(21,33) lies on the equation.  True

The given point  C (99, 137) lies on the equation.  True

Step-by-step explanation:

Here, the given equation is : y =\frac{4}{3} x + 5

Now,check the given equation for the given points.

1)  A (6,13)

Substitute x = 6 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (6) + 5  = 4(2) + 5  = 8 + 5 =  13

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2)  B  (21,33)

Substitute x = 21 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (21) + 5  = 4(7) + 5  = 28 + 5 =  33

⇒ y  = 33

Hence, the given point  B(21,33) lies on the equation.

3)  C (99, 137)

Substitute x = 99 in the given equationy =\frac{4}{3} x + 5

y =\frac{4}{3} (99) + 5  = 4(33) + 5  = 132 + 5 =  137

⇒ y  = 137

Hence, the given point  C (99, 137) lies on the equation.

7 0
3 years ago
Read 2 more answers
Five more than a number is three
Pavel [41]

I'm not sure if you use "x" as your variable, so:

# + 5 = 3 or x + 5 = 3

7 0
3 years ago
Read 2 more answers
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