Question

Take the following measured gauge (or gage) pressures and convert them to absolute pressures in both kPa and psi units for an ambient pressure equal to 98.10 kPa a) pgage 152 kPa, b) Pgage=67.5 Torr, c) pvac 0.10 bar, d) pvac 0.84 atm

Answer 1

Answer:

Explanation:

Given

ambient Pressure =98.10 kPa

(a)gauge pressure 152 kPa

we know

Absolute pressure=gauge pressure+Vacuum  Pressure

$P_{abs}$=152+98.10=250.1 kPa or 36.27 psi

(b)$P_{gauge}$=67.5 Torr or 8.99 kpa

as 1 Torr is 0.133 kPa

$P_{abs}$=8.99+98.10=107.09 kPa or 15.53 psi

(c)$P_{vaccum}$=0.1 bar or 10 kPa

Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi

as 1 kPa is equal to 0.145 psi

(d)$P_{vaccum}$=0.84 atm  or 85.113 kPa

as 1 atm is equal to 101.325 kPa

$P_{abs}$=98.10-85.11=12.99 kPa or 1.88 psi