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BlackZzzverrR [31]
3 years ago
11

How do you relate and explain a planet's distance from the Sun to things like the time of their year & their average tempare

ature
Physics
1 answer:
anzhelika [568]3 years ago
5 0
What we call a "year" is the time a body takes to complete one orbital revolution
in its path around the sun.  The way gravity works, the farther a planet is from the
sun, the slower it moves, and the longer it takes to complete that trip.  So, farther
out from the sun means a longer "year".

Everybody knows that if you want to get more warmth, then you have to stand closer
to the fire, and it's the same with planets.  The farther a planet is from the sun, the less
heat it gets from the sun, and in most cases, that means its average temperature is
lower. (The planet's average temperature is affected by other things besides its distance
from the sun, such as how much heat comes up from inside, and how much heat its
atmosphere traps.)

The farther a planet's rotation axis is tilted from being perpendicular to the plane
of its orbit, the more seasonal variation there can be in the temperature at any one
place on its surface.  Of course, this is kind of irrelevant if the planet has no surface.
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My best guess would be:

"A force equal in magnitude but opposite in direction"

However I assume that this question is multiple choice, by the way it is introduced. Therefore it would be helpful if these options were also displayed - hence take this as my best guess only.
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Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
lana [24]

Answer:

the work done by the 30N force is 4156.92 J.

For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:

W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J

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3 years ago
A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball
jonny [76]

(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s

(b) The work that the racket does on the ball is -35.1 Joule

<h3>Further Explanation</h3>

<u>Given :</u>

mass of ball = m = 0.06 kg

initial velocity = v₁ = -50.4 m/s

final velocity = v₂ = 37.0 m/s

<u>Unknown :</u>

(a) Impulse = I = ?

(b) Work = W = ?

<u>Solution :</u>

<h2>Question (a) :</h2>

In this question , we could use the formula from Second Law of Newton :

I = \Delta p

I = p_2 - p_1

I = m \times v_2 - m \times v_1

I = m \times (v_2 - v_1)

I = 0.06 \times (37.0 - (-50.4))

I = 0.06 \times (87.4)

I = 5.244~kg.m/s

\large { \boxed {I \approx 5.24~kg.m/s} }

<h2>Question (b) :</h2>

W = F \times d

W = (\frac{I}{\Delta t})(\frac {v_1 + v_2}{2} \Delta t)

W = \frac{I(v_1 + v_2)}{2}

W = \frac{5.244(-50.4 + 37)}{2}

W = \frac{5.244(-13.4)}{2}

W = -35.1348~Joule

\large { \boxed {W \approx -35.1~Joule}}

<h3>Learn more</h3>

Newton's Law of Motion: brainly.com/question/10431582

Example of Newton's Law: brainly.com/question/498822

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Newton, Law, Impulse, Work

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