![\bf \cfrac{x}{4x+x^2}\implies \cfrac{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(4+x)}\implies \cfrac{1}{4+x}\qquad \{x|x\in \mathbb{R}, x\ne -4\}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%7D%7B4x%2Bx%5E2%7D%5Cimplies%20%5Ccfrac%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D%7D%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%284%2Bx%29%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B4%2Bx%7D%5Cqquad%20%5C%7Bx%7Cx%5Cin%20%5Cmathbb%7BR%7D%2C%20x%5Cne%20-4%5C%7D)
if you're wondering about the restriction of x ≠ -4, is due to that would make the fraction with a denominator of 0 and thus undefined.
The length of the fencing is 62.4 feet.
The width of the fencing is 17.6 feet.
Given,
The measurement of the Christmas garland = 160 feet
The width of the fencing = w
The length of the fencing, l = 4w - 8
We have to find the length and width of the fencing.
Here,
Perimeter can be taken as 160. Because garland will cover the entire fencing.
Perimeter = 2(l + w)
160 = 2(4w - 8 + w)
160 = 2(5w - 8)
160/2 = 5w - 8
80 + 8 = 5w
88/5 = w
width = 17.6 feet
Now,
l = 4w - 8
l = 4 × 17.6 - 8
l = 70.4 - 8
length = 62.4 feet
That is,
The length of the fencing is 62.4 feet.
The width of the fencing is 17.6 feet.
Learn more about perimeter here:
brainly.com/question/13023749
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11pi/6 is in 4th quadrant.
The reference angle is pi/6 because 11pi/6 is pi/6 radians away from 'x' axis.
In 4th quadrant, sin is negative and cos is positive, therefore tan is negative.
This means:
I think 7 is B and 8 is A, but im not really sure about this so im sorry if this is wrong