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allochka39001 [22]
3 years ago
9

an airplanes altitude changed -531 feet over 9 minutes.what was the mean change of altitude in feet per minute.

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

-59 feet per minute

Step-by-step explanation:

-539/9 = -59

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At Otto’s egg farm, Otto has found that when he charges $0.05 per egg, he sell so many eggs that he cannot keep up with the dema
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Answer:

a) P(c) = xc² + yc + z, and P(.15) = $124, P(.05) = 0, P(.17) = 0. Thus:

(#1) .0225x + .15y + z = 124

(#2) .0025x + .05y + z = 0

(#3) .0289x + .17y + z = 0

Subtracting #2 from #3: (#4) .0264x + .12y = 0

Subtracting #2 from #3: (#5) .02x + .1y = 124

Subtracting 1.2×#5 from #4: .0024x = -148.8 → x= -62000

Using this value of x in #5: -1240 + .1y = 124 → y = 13640

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At this price, his profit would be $223.20

3 0
3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
lidiya [134]
Recall your d = rt,  distance = rate * time.

notice, the distance are the same, say it was "d" miles.

and if car A is travelling at a speed of say "r" mph, then B is going at "r+15" mph.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Car A}&d&r&2\\
\textit{Car B}&d&r+15&1.5
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=2r\\
d=1.5(r+15)\\
----------\\
\boxed{2r}=1.5(r+15)
\end{cases}
\\\\\\
2r=1.5r+22.5\implies 0.5r=22.5\implies r=\cfrac{22.5}{0.5}\implies \boxed{r=\stackrel{mph}{45}}

how far is B going?  well, r + 15.
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Find the next number in the following sequences
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Not sure about the others but
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The amount of water in a barrel decreased is 9 5/8 pints in 7 weeks
gizmo_the_mogwai [7]

Answer:

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3 years ago
Need help will give 15 points
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Answer:

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