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allochka39001 [22]
3 years ago
9

an airplanes altitude changed -531 feet over 9 minutes.what was the mean change of altitude in feet per minute.

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

-59 feet per minute

Step-by-step explanation:

-539/9 = -59

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a. x - 2y = 4

Step-by-step explanation:

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Match each line to its slope
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A is 1/2

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Step-by-step explanation:

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3 years ago
What's the area of this yellow surface? pick one of the options.
Oksi-84 [34.3K]
28 in^2

Divide shape into one rectangle and two squares:

Area of rectangle:
10 x 2 = 20 in^2

Area of one square:
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Multiply that by 2 because we have 2 squares similar in size:
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4 0
3 years ago
X+y=5<br> x×y=6<br> Solve simultaneously with steps
igor_vitrenko [27]

Answer:

(3, 2), (2, 3)

Step-by-step explanation:

x + y = 5

xy = 6

Solve the first equation for x.

x = 5 - y

Substitute 5 - y for x in the second equation.

xy = 6

(5 - y)y = 6

5y - y² = 6

y² - 5y + 6 = 0

Factor.

(y - 2)(y - 3) = 0

y - 2 = 0  or y - 3 = 0

y = 2  or y = 3

Now substitute 2 for y in the first equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

One solution is x = 3; y = 2, or (3, 2).

Now substitute 3 for y in the first equation and solve for x.

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x = 2

Another solution is x = 2; y = 3, or (3, 2).

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7 0
2 years ago
A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe
Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

  • Length of the Larger Rectangle =80+2w
  • Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.

6 0
3 years ago
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