<span>Engineers place tolerance on dimensions since
the when engineers use tolerance, buildings and constructions projects like
tall towers, roads, and bridges become more reliable, strong and stable. In
harnessing tolerance, the end product that is made by the engineers,
specifically buildings like schools, hospitals, malls and skyways are sturdy
and dependable.</span>
Answer:
Explanation:
The collision is elastic so we can use the conservation of momentum
Describe the motion in axis x'
Describe the motion in axis y'
Directly proportional to the product of the two charges and inversely proportional to the square of the distance between them
Answer:
m = 1.45 kg
Explanation:
For this exercise we look for size reduction in height
Reduction = y / y₀
Reduction = 2.15 / 6.75
Reduction = 0.3185
As the statue should not be deformed, all reduction has the same factor.
Let's use the concept of density
ρ = m / V
Initial statue
ρ = m₀ / V₀
It is reduced
V = x y z
V = 0.3185 x₀ 0.3185 y₀ 0.3185 z₀
V = 0.3185³ V₀
Density is
ρ = m / V
ρ = m / 0.3185³ V₀
As the density remains constant we can match them
m₀ / Vo = m / 0.3185³ V₀
m = 0.3185³ m₀
Let's calculate
m = 0.3185³ 45
m = 0.03231 45
m = 1.45 kg
