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katrin2010 [14]
3 years ago
14

A turnip is dropped from a height of 70 meters. How long does it take to hit the ground?

Physics
1 answer:
Bess [88]3 years ago
3 0

Here's a formula for the distance an object falls from rest:

D = (1/2) A T² ... <== MEMORIZE THIS

Distance = (1/2) · (acceleration) · (time²)

On Earth, the acceleration of gravity is always 9.8 m/s².  So for a fall that starts with zero speed, the formula says

70 m = (1/2) (9.8 m/s²) (time²)

70 m = (4.9 m/s²) (time²)

Divide each side by  (4.9 m/s²) ;

time² = (70 m) / (4.9 m/s²)

time² = (70/4.9) sec²

time = √(70/4.9)  seconds

time = 3.78 seconds

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Answer:

a) time taken to catch up with speeding car is 12.25 secs

b) the police car will travel 273.8 m to catch up with the speeding car

Explanation:

Given that;

speed of car V_{c} = 50 mi/hr = 22.352 m/s

acceleration of police car = 10 mi/hr = 4.47 m/s²

V_{f}  = 70 mi/hr = 31.29 m/s

Now time taken to reach maximum speed is t₁

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V_{f} =  V_{i} + at₁

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31.29 = 0 + 4.47t₁

t₁ = 31.29 / 4.47

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time taken to cover Δd will be

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t₂ = 46.96 / ( 31.29 - 22.352 )

t₂ = 46.96 / 8.938

t₂ = 5.25 sec

distance travelled by the police in time t₂ will be

d₂ = V_{f} × t₂

d₂ = 31.29 × 5.25

d₂ = 164.3 m

a) How long will it take before the officer catches up to the speeding car;

time taken to catch up with speeding car;

t = t₁ + t₂

t = 7 + 5.25

t = 12.25 secs

Therefore, time taken to catch up with speeding car is 12.25 secs

b)  how far will it have travelled in order to do so;

distance = d₁ + d₂

distance = 109.5 + 164.3

distance = 273.8 m

Therefore, the police car will travel 273.8 m to catch up with the speeding car

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Thus at every point, the direction of velocity vector changes and this means the velocity is never constant. The objects in uniform circular motion has centripetal acceleration which means that velocity vector of the planet points toward the center of the  circle.

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