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Alchen [17]
3 years ago
5

A student attaches a block to a vertical spring of unknown spring constant so that the block-spring system will oscillate if the

block-spring system is released from rest at a vertical position that is not the system’s equilibrium position. The student varies the object’s mass and uses a stopwatch to determine the time it takes the object to make one oscillation. The student creates the graph that is shown. The slope of the line of best fit is equal to which of the following quantities?

Physics
2 answers:
Talja [164]3 years ago
8 0

Answer:

D: 2π/√k0

Explanation:

I got it right

chubhunter [2.5K]3 years ago
3 0

Answer:

x axis

Explanation:

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A 39.5 kg child stands at the center of a 125 kg playground merry-go-round which rotates at 3.10 rad/s. If the child moves to th
Neporo4naja [7]
Using the law of conservation of angular momentum, we have 

<span>I1 w1 = I2 w2 </span>

<span>ie., m1r^2/2 x w1 = ( m1r^2/2 + m2r^2 ) w2 </span>

<span>ie., new angular velocity w2 = m1 w1 / ( m1+ 2m2) = 125 x 3.1 / ( 125 + 2 x39.5 ) </span>

<span>= 1.8995 = 1.9 rad /sec ( nearly )</span>
3 0
4 years ago
A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Appr
Ludmilka [50]

Answer:

The pitch that he hears after the truck passes and is moving away is 819.6 Hz.

Explanation:

The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:    

f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}}

Where:

f: is the perceived frequency

f_{0}: is the emitted frequency

v_{s}: is the speed of sound = 340 m/s

v_{o}: is the speed of the observer = 0 (he is not moving)

v_{f}: is the speed of the fire truck

First, we need to find the speed of the fire truck. When it approaches the observer we have:

f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}}

950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}}

v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz}

v_{f} = 25.05 m/s

Hence, the speed of the fire truck is 25.05 m/s.

Now, we can calculate the pitch that the observer hears after the truck passes:

f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}}

f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s}

f = 819.6 Hz

Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.

I hope it helps you!                                                          

7 0
3 years ago
Justine is ice-skating at the Lloyd Center. What is her final velocity if she accelerates at a rate of 2.0 m/s for 3.5 seconds?
belka [17]

Answer:

7 m/s

Explanation:

Acceleration, a=\frac {v-u}{t}

Where v and u are the final and initial velocities of the Justine respectively, t is the time taken for Justin to attain final velocity.

Making v the subject then

v=at+u

Taking u as zero then

Substituting 3.5 for t, 2 as a then

v=3.5*2=7 m/s

8 0
3 years ago
Five-gram samples of copper and aluminum are at room temperature. Both receive equal amounts of energy due to heat flow. The spe
laila [671]

m₁ = mass of sample of copper = m₂ = mass of sample of aluminum = 5 g

T = initial temperature of copper = initial temperature of aluminum

T₁ = final temperature of copper

T₂ = final temperature of aluminum

c₁ = specific heat of copper = 0.09 cal/g°C

c₂ = specific heat of aluminum = 0.22 cal/g°C

Since both receive same amount of heat, hence

Q₁ = Q₂

m₁ c₁ (T₁ - T) = m₂ c₂ (T₂ - T)

(5) (0.09) (T₁ - T) = (5) (0.22) (T₂ - T)

T₁ - T = (2.44)  (T₂ - T)

Change in temperature of copper = (2.44) change in temperature of aluminum

hence the correct choice is

c. The copper will get hotter than the aluminum.

4 0
3 years ago
Read 2 more answers
A package was determined to have a mass of 5.7 kg what's the force of gravity acting on the package on Earth
Natalka [10]

Given that,

mass m= 5.7 kg

Force of gravity = ?

Since,

Force of gravity acting on earth is equal to the weight and

W= mg

W= 5.7 * 9.81

W= 55.917

or

W= 56 N

Force of gravity acting on Earth by the package is 56 N.

6 0
3 years ago
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