Answer:
5 m/s
Explanation:
Horizontal distance traveled, x = 2 m
vertical distance traveled, y = 4/5 m
Let the speed of cup as it leaves the counter is v and it takes time t to hit the ground.
Use second equation of motion in vertical direction
Here acceleration in vertical direction is 9.8 m/s^2.
So,
t = 0.4 second
Now in horizontal direction the acceleration in zero.
Horizontal distance = horizontal velocity x time
x = v t
2 = v (0.4)
v = 5 m/s
Thus, the horizontal velocity of cup as it leaves the counter is 5 m/s.
Answer:
Class 1 Levers: Moving the fulcrum closer to the load will increase the mechanical advantage. Moving the effort farther from the fulcrum will increase the mechanical advantage.
Explanation:
Hope it helps you
To solve this problem, we can use the cosine formula for
calculating the length of the displacement:
c^2 = a^2 + b^2 – 2 a b cos θ
where c is the displacement, a = 3.5 km, b = 4.5 km, and θ
is the angle inside the triangle
Since the geeze turned 40° from west to north, so the
angle inside the triangle must be:
θ = 180 – 40 = 140°
c^2 = 3.5^2 + 4.5^2 – 2 (3.5) (4.5) cos 140
c^2 = 56.63
c = 7.53 km
<span>So the magnitude of the displacement is 7.53 km</span>
<span> static friction :) your very welcome
</span>
Answer:
B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.
Explanation:
In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential
so according to the given situation, the option b is correct
And, the rest of the options are wrong
