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lord [1]
3 years ago
7

Express 6009m in scientific notation

Chemistry
2 answers:
ElenaW [278]3 years ago
8 0

Answer:

The number 6009 in scientific notation is 6.009*10³

Explanation:

Scientific notation is a quick way to represent a number using base ten powers. This notation is used to express very large or very small numbers very easily.

The numbers are written as a product a*10ⁿ where:

  • a is a real number greater than or equal to 1 and less than 10, to which a decimal point is added after the first digit if it is a number that is not an integer.
  • n is an integer, which receives the name of exponent or order of magnitude. Represents the number of times the comma moves. It is always an integer, positive if it moves to the left, negative if it moves to the right.

To write the number 6009 in scientific notation, the following steps are performed:

  • The decimal point moves to the left as many spaces until it reaches the right of the first digit.  In this case: 6009=6.009
  • This number is then written, which will be the coefficient a in the expression of the previous product.
  • The base 10 is written with the exponent equal to the amount of spaces that the comma moves. This is a positive number because the comma moves to the left. So in this case: the exponent will be 3

Then <u><em>the number 6009 in scientific notation is 6.009*10³</em></u>

Andre45 [30]3 years ago
4 0
6.009 x 10^3. You have to put 6009 into a decimal that is less than 10. Count backwards from 9 until you get to a single digit. You would move the decimal back three places making it 10^3
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Computer, Microprocessor, Cell Phone, WWW, iPhone

Explanation:

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6 0
2 years ago
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A solution of phosphoric acid was made by dissolving 10.8 g of H3PO4 in 133.00 mL of water. The resulting volume was 137 mL. Cal
Nesterboy [21]

Answer:

Density is: 1.05 g/ml

Mole fraction solute: 0.015

Mole fraction solvent:  0.095

Molarity: 0.80 M

Molality: 0.82 m

Explanation:

A typical excersise of solution.

It is more confortable to make a table for this.

                |   masss  |  volume  |  mol

solute       |                |                |          

solvent     |                |                |  

solution    |                |                |

Let's complete, what we have.

                 |   masss  |  volume  |  mol

solute       |  10.8g     |                |          

solvent     |                |  133 mL   |  

solution    |                |  137 mL    |

We can first, know how many moles are 10.8 g

Molar Mass H3PO4 = 97.99 g/mol

Mass / Molar mass = mol

10.8 g / 97.99 g/m = 0.110 mol

Density of water is 1 g/ml (it is a very knowly value)

From this data, we can know water mass, solvent.

Density = mass / volume

1 g/ml = mass / 133 mL

Mass = 133 g

We can also have the moles, by the molar mass of water 18 g/m

133 g / 18 g/m = 7.39 mol

                 |   masss  |  volume  |  mol

solute       |   10.8g     |                |   0.110 mol      

solvent     |   133g      |  133 mL   |  7.39 mol

solution    |   143.8g   |  137 mL   | 7.50 mol

Mass of solution will be solute mass + solvent mass

Moles of solution will be solute moles + solvent moles

Now we can calculate everything.

Molarity means mol of solute in 1 L of solution. (mol/L)

We have to convert 137 mL in L (/1000)

0.137L so → 0.110 m / 0.137L = 0.80 M

Molality means mol of solute in 1kg of solvent.

We have to convert 133g in kg (/1000)

0.133 kg so → 0.110 m/0.133 kg = 0.82 m

Density is mass / volume

Solution density will be solution mass / solution volume

143.8 g/137 mL = 1.05 g/m

Molar fraction is : solute moles / total moles  or  solvent moles/total moles.

You can also (x 100%) to have a percent of them.

Remember sum of molar fraction = 1

Molar fraction of solute = 0.110 mol / 7.50mol = 0.015

Molar fraction of solvent = 7.39 mol / 7.50 mol = 0.985

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Answer:

Explanation:

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In this case, the temperature went down. The reaction is Endothermic.

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3. Give one example of an element and one
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Answer:

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f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

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mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

3 mole of NaOH required ------- 1 mole of H3PO4

0.00472mole of NaOH ----------x

cross multiply

3x = 0.0472

x = 0.00157mole

[H3PO4] = mole of H3PO4 / Vol. of H3PO4

= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
7 0
2 years ago
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