8 moles of water on the right side.
An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).
Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.
Step 1:
MnO4- ----> Mn2+
2Cl- ------> Cl2
Step 2:
MnO4- --> Mn2+ + 4H2O
2Cl- -----> Cl2
Step 3:
8H+ + MnO4- ------> Mn2+ + 4H2O
2Cl- ----->Cl2
Step 4:
8H+ + MnO4- +5e- ------>Mn2+ + 4H2O
2Cl- ----> Cl2+ 2e-
Step 5:
16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2
This is the balanced equation in an acidic medium.
That is 8, right side.
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Answer:
1.634 molL-1
Explanation:
The mol ration between NH3 and HCl is 1 : 1
Using Ca Va / Cb Vb = Na / Nb where a = acid and b = base
Na = 1
Nb = 1
Ca = 0.208 molL-1
Cb = ?
Va = 19.64 mL
Vb = 25.00mL
Solving for Cb
Cb = Ca Va / Vb
Cb = 0.208 * 19.64 / 25.0
Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)
Using the dilution equation;
C1V1 = C2V2
Initial Concentration, C1 = ?
Initial Volume, V1 = 25.00 mL
Final Volume, V2 = 250 mL
Final Concentration, C2 = 0.1634 molL-1
Solving for C1;
C1 = C2 * V2 / V1
C1 = 0.1634 * 250 / 25.00
C1 = 1.634 molL-1
Explanation:
At each reflecting surface (benzene and glass) there will be 180 degree phase change.
Now, for constructive interference the optical path in benzene is 
.
Formula to calculate thickness of a benzene thin film is as follows.
Optical path length through benzene () = 
Hence, substituting the given values into the above formula as follows.
Optical path length through benzene =
d = 
= 
= 
(as 1 nm = 
= 204.9 m
Thus, we can conclude that minimum thickness of benzene is 204.9 m.
Formal charge on sulphur in SO2 is:
Hence, neither an electron is gained nor it is lost. Hence, neither negative nor positive charge is present on S atom. Hence, the formal charge on S atom in SO2 is zero.
