Explanation:
I think the answer is 2nd
the anwser would most likely be j=0
OK in the case of hydrazine 14 grams of nitrogen combine with 2 gram of hydrogen and with ammonia 14 grams combine with 3 grams of hydrogen.
Ratio 2:3
Answer:
-26.125 kj
Explanation:
Given data:
Mass of water = 250.0 g
Initial temperature = 30.0°C
Final temperature = 5.0°C
Amount of energy lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 5.0°C - 30.0°C
ΔT = -25°C
Specific heat of water is 4.18 j/g.°C
Now we will put the values in formula.
Q = m.c. ΔT
Q = 250.0 g × 4.18 j/g.°C × -25°C
Q = -26125 j
J to kJ
-26125 j ×1 kj /1000 j
-26.125 kj
<span>The only scenario that
will allow you to reach an equilibrium mixture involving these chemicals is to
place NH3 into a sealed vessel. This reaction requires pressures between 2100,
3600 psi, and temperatures between 300 and 550 degree Celsius. With this given
temperature and pressure, the ammonia naturally decomposes into nitrogen and
hydrogen gas at the same rate. When this happen, the concentrations of these
chemicals become constant and the system is said to be at equilibrium.</span>
