There are 2 peaks are in the proton spin decoupled 13C NMR spectrum of 1,3,5-trinitrobenzene .
The 13C NMR spectrum give the peak which is directly about the carbon skeleton not just the proton attached to it . The number of signals tell us how many different carbons or set of equivalent carbons . The splitting of a signal tells us how many hydrogens are attached to each carbon.
In 1,3,5-trinitrobenzene molecule , there are 2 peaks are in the proton spin decoupled 13C NMR spectrum three carbon give one signal and another three carbon give another one signal .
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Answer:
12.044 X 10^23 molecules of NaOH
Explanation:
because NaOH is an ionic bond, we should be asking how many <em>formula units </em> are in 2 moles of NaOH, there are 0 molecules since NaOH is measured in formula units.
but for the sake of the problem I'll assume NaOH is measured in molecules
for every mol of something there are 6.022 X 10^23 of something of that something.
so there are 6.022 X 10^23 molecules for every mol of NaOH
that means we have 2 X 6.022 X 10^23 molecules in 2 moles of NaOH = 12.044 X 10^23 molecules of NaOH
The concentration of the basic solution is determined by:
N = (number of moles / volume of solution)
number of moles = 1.09 x 10^-2 mol
volume of solution = 1 liter
N of basic solution = 1.09 x 10^-2 mol / 1 liter
N = 1.09 x 10^-2 mol/L
The initial concentration of Zn (OH)2 is 0; the basic solution is 1.09x10^-2 M, then the concentration of OH in the final solution is 1.09x10^-2 M
