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Leviafan [203]
3 years ago
12

An element A has an atomic number of 11 and another element B has an atomic number 17 (A

Chemistry
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

Agroup one.B group seven. lonic/electrovalent bonding.

sodium chloride, 2,8. 2,8,8

Explanation:

the reason why it is an lonicbonding is because it is a force of attraction between opposite charges.it involves the transfer of electrons from a metal to a non-metal.

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How many oxygen atoms are there in 0.25 mole of CO2?
Anna35 [415]

Answer:

It is known that 1 mol of a molecule contains 6.023×1023 6.023 × 10 23 number of molecules. So, 0.25 moles of CO2 C O 2.

3 0
3 years ago
What principal quantum number refers to:
docker41 [41]
The principle quantum number "n" represents the relative overall energy of each orbital, and the energy of each orbital increases as the distance from the nucleus increases. The sets of orbitals with the same "n" value are often referred to as electron shells or energy levels. 
4 0
3 years ago
Is the asthenosphere or the lithosphere closer to the outer core
Murrr4er [49]
The asthenosphere is directly below the lithosphere so the answer to your question is the asthenosphere, because the outer core is towards the center of Earth.
4 0
3 years ago
A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
3 years ago
What are the common parts of a nucleotide?
a_sh-v [17]
1. Phosphate Group,Pentose sugar, and Nitrogen base
2. Not sure
3.These are found in RNA cytosine, guanine, adenine and uracil.
8 0
3 years ago
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