Answer:
b) Delta S < 0
Explanation:
The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).
- If Δn(g) > 0, the entropy increases (ΔS > 0).
- If Δn(g) < 0, the entropy decreases (ΔS < 0).
- If Δn(g) = 0, there is little or no change in the entropy
Let's consider the following equation.
2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)
Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.
Energy levels are considered orbitals.
Answer:
The right lower quadrant
The left lower quadrant
Explanation:
Those quadrants contain the ovaries and I just got it correct on the assignment.
The base conjugate acid pair when strong acid is added to methylamine CH3NH2 is
base CH3NH2; conjugate acid: CH3NH3 +
Explanation
When a base CH3CH2 accept proton it form its conjugate acid which known as methyl ammonium ion. Therefore conjugate acid of CH3CH2 is CH3NH3+ ion
For example when CH3CH2 react with HCl
CH3CH2 +HCl → CH3CH3+ + Cl-
Answer:
Plant and animal cells differ in that plants have a large central vacuole, while animals have smaller vacuoles. Plant cells also have cell walls and plastids, while animal cells do not.