Molecular motion is a measure of the movement of the molecules in a substance. Molecular motion is substantially different betwe
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The pressure exerted by the block on the table is given by:
where W is the weight of the box, and A is the bottom surface area of the box.
The weight of the box is:
Substituting into the first equation, we find the pressure:
Answer:
0.01606 Newtons
Explanation:
r = Distance between the asteroid and Sally = 17000000 m
m₁ = Mass of the asteroid = 8.7× 10²⁰ kg
m₂ = Mass of Sally = 80 kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
From Newton's Universal law of gravity
The force Sally experiences is 0.01606 Newtons
Answer:
Assuming that both mass here move horizontally on a frictionless surface, and that this spring follows Hooke's Law, then the mass of would be four times that of
.
Explanation:
In general, if the mass in a spring-mass system moves horizontally on a frictionless surface, and that the spring follows Hooke's Law, then
.
Here's how this statement can be concluded from the equations for a simple harmonic motion (SHM.)
In an SHM, if the period is , then the angular velocity of the SHM would be
.
Assume that the mass starts with a zero displacement and a positive velocity. If represent the amplitude of the SHM, then the displacement of the mass at time
would be:
.
The velocity of the mass at time would be:
.
The acceleration of the mass at time would be:
.
Let represent the size of the mass attached to the spring. By Newton's Second Law, the net force on the mass at time
would be:
,
Since it is assumed that the mass here moves on a horizontal frictionless surface, only the spring could supply the net force on the mass. Therefore, the force that the spring exerts on the mass will be equal to the net force on the mass. If the spring satisfies Hooke's Law, then the spring constant will be equal to:
.
Since , it can be concluded that:
.
For the first mass , if the time period is
, then the spring constant would be:
.
Similarly, for the second mass , if the time period is
, then the spring constant would be:
.
Since the two springs are the same, the two spring constants should be equal to each other. That is:
.
Simplify to obtain:
.