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LekaFEV [45]
3 years ago
13

Turning a magnet very quickly would be BEST used to create A) radiation. Reactivate B) light waves. Reactivate C) an electric cu

rrent. D) a convection current.
Physics
2 answers:
Andreyy893 years ago
4 0

Answer: C) an electric current

Explanation:

Changing magnetic field induces electromotive force which results in electric current to flow in conducting wire.

<u>From Faraday's Law:</u>

induced emf,

e = -N \frac{\Delta B A}{\Delta A}

Thus, when magnet is quickly turned, a change in magnetic field would produce an electric current.

Softa [21]3 years ago
3 0
<h2>Answer:</h2>

<u>Turning a magnet very quickly would be BEST used to create an electric current</u>

<h2>Explanation:</h2>

In Electromagnetic waves electric field produces magnetic field and vice versa. A moving magnet can produce electric current. Dynamo is the best example for it. In dynamo armature is rotated between the magnets which results in the development of electric field and hence an electric current is produced in it.

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How do you find the angle (to the nearest tenth) on your graph that produced the greatest range, based on the line of best fit?
VikaD [51]

Answer:

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Explanation:

3 0
3 years ago
Can you please answer this question?
Sidana [21]
I think its b too but i may be wrong
5 0
3 years ago
Dolphin echolocation is similar to ultrasound. Reflected sound waves
s344n2d4d5 [400]

Answer:

Waves with high frequencies have shorter wavelengths that work better  than low frequency waves for successful echolocation.

Explanation:

To understand why high-frequency waves work better  than low frequency waves for successful echolocation, first we have to understand the relation between frequency and wavelength.

The relation between frequency and wavelength is given by

λ = c/f

Where λ is wavelength, c is the speed of light and f is the frequency.

Since the speed of light is constant, the wavelength and frequency are inversely related.

So that means high frequency waves have shorter wavelengths, which is the very reason for the successful echolocation because waves having shorter wavelength are more likely to reach and hit the target and then reflect back to the dolphin to form an image of the object.

Thus, waves with high frequencies have shorter wavelengths that work better  than low frequency waves for successful echolocation.

3 0
3 years ago
An automobile with a standard differential turns sharply to the left. The left driving wheel turns on a 20-m radius. Distance be
Inessa05 [86]

Explanation:

The given data is as follows.

    Inner wheel Radius = 20 m,

   Distance between left and right wheel = 1.5m,

Let us assume speed of drive shaft is N rpm.

Formula to calculate angular velocity is as follows.

    Angular velocity of automobile = w = \frac{V}{R}

where,   V = linear velocity of automobile m/min,

              R = turning radius from automobile center in meter

In the given case, angular velocity remains same for inner and outer wheel but there is change in linear velocity of inner wheel and outer wheel.

Now, we assume that

         u = linear velocity of inner wheel

and,   u' = linear velocity of outer wheel.

Formula for angular velocity of inner wheel w = ,

Formula for angular velocity of outer wheel w =

Now, for inner wheels

                   w =

                      = \frac{u}{(R - d)}

                  u = V \times \frac{(R - d)}{R}

                    = V \times (1 - \frac{d}{R})

If radius of wheel is r it will cover  distance in one min.

Since, velocity of wheel is u it will cover distance u in unit time(min)

Thus,             u = 2\pi rn = V \times (1 - \frac{d}{R})

Now, rotation per minute of inner wheel is calculated as follows.

         n = \frac{V}{2 \pi r \times (1 - \frac{d}{R})}

            = \frac{V}{2 \pi r \times (1 - \frac{0.75}{20})} (since 2d = 1.5m given, d = 0.75m),

             = \frac{V}{r} \times 0.1532

So, rotation per minute of outer wheel; n' =  

                   = \frac{V}{2 \pi r \times (1 + \frac{0.75}{20})}

                   = \frac{V}{r} \times 0.1651

5 0
3 years ago
Which is the best definition of a parallel
Oksanka [162]

A parallel circuit exists when an electric charge flows in more than one path best describes it.

<h3>What is a Parallel circuit?</h3>

This type of circuit has branches in which the current divides and only part of it flows through any of the branch.

Parallel circuit having more than one branch therefore means that electric charge will flow in more than one path thereby making option A the most appropriate choice.

Read more about Parallel circuit here brainly.com/question/12069231

5 0
2 years ago
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