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Keith_Richards [23]
3 years ago
9

Please Help........................................................

Mathematics
1 answer:
larisa [96]3 years ago
8 0

2(n-5)\geq2n+10\\2n-10\geq2n+10\\-10\geq 10\\n\in\emptyset

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HELPPPPP HELPPPPP HELPPPP!!!!! AHHHHHHHHHHHHHHJJJJSJDJDJ
erica [24]

Answer:

QRS equals to 91

Step-by-step explanation:

50 + 41 = 91

8 0
2 years ago
The length of a rectangle is 3 inches longer than its width. If the perimeter of the rectangle is 54 inches, find it’s length an
dangina [55]

Answer: Length = 15, Width = 12

Step-by-step explanation:

L = length

W = width

L = W+ 3

perimeter = 2L + 2W

54 = 2(W+3) + 2W

54 = 2W + 6 + 2W

54 = 4W + 6

54 - 6 = 4W

48 = 4W

W = \frac{48}{4}

W = 12

now to find the length, plug the width into the equation L = W + 3

length:

L = W+3

L=12 +3

L = 15

6 0
3 years ago
How much would $500 invested at 4% interest compounded continuously be worth after 7 years, round to the nearest cent
jarptica [38.1K]
Should be about $661.56
5 0
3 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
Solve for x using the property of bisected<br> diagonals<br> CN=20 ln=6x-2
kari74 [83]

Answer:

Step-by-step explanation:

abc

6 0
3 years ago
Read 2 more answers
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