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4 years ago

Select the correct answer from each drop-down menu.

Physics

2 answers:

Natali [406]4 years ago

6 0

Answer:

A. ) alloys

B. ) main

Explanation:

hichkok12 [17]4 years ago

3 0

Brass and bronze are both <u>alloys</u>(A) of copper because copper is the <u>main</u>(B) component in brass and bronze.

<u>Explanation: </u>

Brass and Bronze are used in our day to day life known as metal alloys. Brass is an alloy of the metals like copper and zinc which has high percentage of metal copper with tin combined with it.

Brass is dull yellow in color. Bronze is reddish brown in color. Brass was known to be present in 500 BC. Bronze was about 3500 BC known to be present. Thus Bronze and Brass are both alloys of the metal copper since the main component in the brass and bronze is copper.

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An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m

ddd [48]

Answer:

Velocity of electron will be $1.325\times 10^6m/sec$

Explanation:

We have given distance across the plate d = 2 mm $=2\times 10^{-3}m$

Potential difference V = 6 volt

We know that potential difference at any distance is given by

V = Ed , here V is potential difference, E is electric field and d is distance

So $E=\frac{V}{d}=\frac{6}{2\times 10^{-3}}=3000N/C$

Charge on electron $e=1.6\times 10^{-19}C$

We know that expression of velocity is given by $v=\sqrt{\frac{2qEd}{m_e}}$ , here q is charge on electron, E is electric field and d is distance

So $v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 3000\times 3000}{9.11\times 10^{-31}}}=1.325\times 10^6m/sec$

8 0

4 years ago

Which factor should change when comparing the boiling times of the liquids?

Andru [333]

Answer: B

Explanation:

7 0

3 years ago

Read 2 more answers

A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t

Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

$h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m$

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height is given by;

v = u - gt

u = gt

$t = \frac{u}{g}$

Time of flight, T = 2t

$T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s$

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0

3 years ago

HELP ASAP!!

Nimfa-mama [501]

The strength of the magnetic field is equal to 20 Tesla.

<h3>Explanation:</h3>

Given:

Induced potential difference = V = 12 V

Length of wire = L = 0.20 m

Speed of the moving wire = V = 3.0 m/s

Magnetic field strength = B = ?

A conductor, placed in a uniform magnetic field; when moved at a constant speed with respect to the field, leads to a changing magnetic flux, generating an electromotive force (EMF). Using, Faraday's law of magnetic induction, a moving conductor's induced EMF in terms of the magnetic field strength is given by :

$E = L\times V\times B$ ......................(1)

where

E = Induced potential difference (EMF)

L = Length of the conductor

V = Speed of the conductor moved with respect to the magnetic field

B = Strength of uniform magnetic field

Rewriting equation (1) for B, we get

$B = \frac{E}{L\times V} = \frac{12}{0.2\times 3} = \frac{12}{0.6} = 20\ T$

The strength of magnetic field is equal to 20 Tesla.

7 0

4 years ago

When the point of reference (the observer) is in motion, it flips the "rules" of vector addition (you ADD the vectors going in o

KengaRu [80]

Answer:

the statement is TRUE

Explanation:

When we move in the same direction, the relative speed of the two vehicles is lower, so we must subtract their speeds, if the result is positive the vehicles approach and if it is negative they move away.

v_relative = v₁ - v₂

When the two vehicles go in opposite directions, the speed is much higher, so we must add their speeds

v_relative = v₁ - (-v₂))

v_relative = v₁ + v₂

therefore the statement is TRUE

3 0

3 years ago