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4 years ago

HELP ASAP!!

Physics

1 answer:

Nimfa-mama [501]4 years ago

7 0

The strength of the magnetic field is equal to 20 Tesla.

<h3>Explanation:</h3>

Given:

Induced potential difference = V = 12 V

Length of wire = L = 0.20 m

Speed of the moving wire = V = 3.0 m/s

Magnetic field strength = B = ?

A conductor, placed in a uniform magnetic field; when moved at a constant speed with respect to the field, leads to a changing magnetic flux, generating an electromotive force (EMF). Using, Faraday's law of magnetic induction, a moving conductor's induced EMF in terms of the magnetic field strength is given by :

$E = L\times V\times B$ ......................(1)

where

E = Induced potential difference (EMF)

L = Length of the conductor

V = Speed of the conductor moved with respect to the magnetic field

B = Strength of uniform magnetic field

Rewriting equation (1) for B, we get

$B = \frac{E}{L\times V} = \frac{12}{0.2\times 3} = \frac{12}{0.6} = 20\ T$

The strength of magnetic field is equal to 20 Tesla.

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Answer:

s = 3.84 x 10⁸ m

Explanation:

The distance traveled by an object, while in uniform motion, is given by the following equation:

s = vt

where,

s = distance covered

v = speed

t = time interval

In this case:

s = distance between Moon and Earth = ?

v = speed of radio waves = 3 x 10⁸ m/s

t = time taken to travel = 1.28 s

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s = (3 x 10⁸ m/s)(1.28 s)

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4 years ago

If a behavior tends to increase after a consequence occurs, that consequence is most likely used as.

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3 years ago

16 grams of ice at –32°C is to be changed to steam at 182°C. The entire process requires _____ cal. Round your answer to the nea

ICE Princess25 [194]

Answer:

12432 cal.

Explanation:

The process to change ice at -32 ºC to steam at 182 ºC can be divided into 5 steps:

1. Heat the ice to 0 ºC, which is the fusion temperature.

2. Melt the ice (obtaining liquid water), which is a process at constant pressure and temperature, so the liquid obtained is also at 0ºC.

3. Heat the liquid water from 0 ºC to 100 ºC, which is the vaporization normal temperature of the water.

4. Vaporization of all the water; this is also a process that occurs at constant pressure and temperature, so the produced steam will be at 100ºC.

5. Heat the steam from 100 ºC to 182 ºC.

Each process has a required energy, and the sum of the energy required for each and all of the steps is the total amount of energy required for the whole process:

$E_T=E_1+E_2+E_3+E_4+E_5$

$E_1$ is a heating process for the ice, so we know that the energy required is proportional to the temperature difference through the specific heat:

$E_1=m*Cp_{sol}*(T_2-T_1)\\E_1=16g*0.5\frac{cal}{gC}*(0-(-32))=256cal$

$E_2$ is a phase change process, so we do not use the specific heat (sensible heat), but the fusion heat (latent heat), so:

$E_{2}=m*dh_{f}={16g*80\frac{cal}{g}}=1280cal$

Analogously,

$E_3=m*Cp_{liq}*(T_3-T_2)=16g*1.00\frac{cal}{gC}*(100-0)C = 1600 cal$

$E_{4}=m*{dh_{vap}}\\\\E_4=16g*540\frac{cal}{g} =8640cal$

$E_{5}=m*Cp_{vap}*(T_{5}-T_{4})\\E_{5}={16g*0.5\frac{cal}{gK}*(182-100)K}=656cal$

Finally, the total energy required is:

$E_T=256cal+1280cal+1600cal+8640cal+656cal\\E_T=12432cal$

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