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Ira Lisetskai [31]
3 years ago
7

Explain the meaning of work done and give examples

Physics
2 answers:
Setler79 [48]3 years ago
7 0

Answer:

the situation in which the force or any kinds of things rhat are done by force is called work done.ex.typed,wrote

miv72 [106K]3 years ago
5 0

Answer:

<h2>WORK DONE on a body is the product of</h2><h3>FORCE IN THE DIRECTION OF DISPLACEMENT AMD DISPLACEMENT.</h3>

WORK ONLY HAS MAGNITUDE AND NO DIRECTION.

  • FORCE applied IN the direction of displacement × displacement = POSITIVE WORK DONE
  • FORCE applied OPPOSITE to the direction of displacement × displacement = NEGATIVE WORK DONE
  • FORCE applied PERPENDICULAR to the direction of displacement × displacement = ZERO WORK DONE

hope it helps

have a nice day

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We use __force to do different force. 1) pulling 2)pushing 3)gravity 4)muscular
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gravity

Explanation:

We use gravity to do different force.

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What is the difference in the speed of the generator with a small magnet and a generator with a large magnet?
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Read 2 more answers
ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give
Alexandra [31]

Answer:

About 8.3 minutes

Explanation:

Use the formula for velocity as the distance covered by the light divided the time it takes: [tex]velocity=\frac{distance}{time}[/tex]

Use the information about the speed of light in vacuum: 300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}

and the information you are given regarding the distance between Sun and Earth: 1.5 * 10^{11} m

to solve the first velocity equation for the unknown time "t":

velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s

we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes

5 0
3 years ago
Assume the radius of an atom, which can be represented as a hard sphere, is r = 1.95 Å. The atom is placed in a (a) simple cubic
Nuetrik [128]

Answer:

(a) A = 3.90 \AA

(b) A = 4.50 \AA

(c) A = 5.51 \AA

(d) A = 9.02 \AA

Solution:

As per the question:

Radius of atom, r = 1.95 \AA = 1.95\times 10^{- 10} m

Now,

(a) For a simple cubic lattice, lattice constant A:

A = 2r

A = 2\times 1.95 = 3.90 \AA

(b) For body centered cubic lattice:

A = \frac{4}{\sqrt{3}}r

A = \frac{4}{\sqrt{3}}\times 1.95 = 4.50 \AA

(c) For face centered cubic lattice:

A = 2{\sqrt{2}}r

A = 2{\sqrt{2}}\times 1.95 = 5.51 \AA

(d) For diamond lattice:

A = 2\times \frac{4}{\sqrt{3}}r

A = 2\times \frac{4}{\sqrt{3}}\times 1.95 = 9.02 \AA

6 0
3 years ago
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