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3 years ago

Write the chemical symbols for three different atoms or atomic cations with 10 electrons.

Chemistry

2 answers:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:

Neon = Ne

Sodium Cation = Na⁺

Magnesium Cation = Mg⁺⁺

Explanation:

Ions are generated when an atom or of atoms gains or looses electrons. When an atom gains electrons it is converted into Anions (with -ve charge) and when it looses electrons it is converted into Cations (with +ve charge).

Hence, Cations are those species which contain positive charge.

As we know Neon is the noble element with atomic number 10 and contains 10 electrons in neutral state. Hence, it is the atom with 10 electrons.

While Sodium has 11 electrons in its neutral state with following electronic configuration.

1s², 2s², 2p⁶, 3s¹

The valence electron in 3rd shell can be easily donated by sodium atom as the resulting stable configuration will be of a noble gas. Hence forming Na⁺.

Also, Magnesium has 12 electrons in its neutral state with following electronic configuration.

1s², 2s², 2p⁶, 3s²

The valence electrons in 3rd shell can be easily donated by magnesium atom as the resulting stable configuration will be of a noble gas. Hence forming Mg⁺².

damaskus [11]3 years ago

4 0

The chemical symbols for 10 different atomic cations with 10 electrons are: Ne, Na⁺, Mg²⁺, Al³⁺

<h3><em>Further explanation </em></h3>

In an atom there are levels of energy in the skin and sub skin.

This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub skins in the skin of an atom, namely s, p, d and f. The maximum number of electrons for each sub skin is

s: 2 electrons

p: 6 electrons

d: 10 electrons and

f: 14 electrons

Charging electrons in the sub skin uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

Each sub-skin also has an orbital depicted in the form of a square in which there are electrons symbolized by half arrows.

An atom or cation that has 10 electrons means having an electron configuration as follows:

1s², 2s², 2p⁶

Judging from this configuration, the elements are in period 2 and group 8A

So the elements that meet are Ne

Whereas cations that meet 10 electrons are elements that release electrons so that they correspond to the electron configuration of the element Ne

and this element is located in period 3

This element is:

Na: [Ne] 3s¹

Na releases 1 electron into Na⁺ so that it matches the electron Ne configuration

Mg: [Ne] 3s²

Mg releases 2 electrons into Mg²⁺ so that it matches the electron Ne configuration

Al: [Ne] 3s² 3p1¹

Al releases 3 electrons into Al³⁺ so that it matches the electron Ne configuration

<h3><em>Learn more </em></h3>

element X

brainly.com/question/2572495

electrons and atomic orbitals

brainly.com/question/1832385

about subatomic particles statement

brainly.com/question/3176193

Keywords: electron configurations, the skin of atoms, Ne, Na⁺, Mg²⁺,Al³⁺

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andrew-mc [135]

Answer:

(a) Covalent bond. NF₃ (nitrogen trifluoride)

(b) Ionic bond. LiCl (lithium chloride)

Explanation:

Nitrogen and fluorine are nonmetals, with high and similar electronegativities, so they form covalent bonds, in which they share pairs of electrons to complete the octet in their valence shell. N has 5 valence electrons so it will form 3 covalent bonds while each Cl has 7 valence electrons so it will form 1 covalent bond. As a result, the empirical formula is NF₃ (nitrogen trifluoride).

Lithium is a metal and Chlorine is a nonmetal. They have different electronegativities so they form an ionic bond, in which Cl gains 1 electron (7 valence e⁻) and Li loses 1 electron (1 valence e⁻). The empirical formula is LiCl (lithium chloride).

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3 years ago

The Haber Process is the main industrial procedure to produce ammonia. The reaction combines nitrogen from air with hydrogen mai

Firdavs [7]

Answer:

A) $N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$ .

B) $Kc=0.0933$ .

C) 0.9 mol.

D) Increasing both temperature and pressure.

Explanation:

Hello,

In this case, given the information, we proceed as follows:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

B) For the calculation of Kc, we rate the equilibrium expression:

$Kc=\frac{[NH_3]^2}{[N_2][H_2]^3}$

Next, since at equilibrium the concentration of ammonia is 0.6 M (0.9 mol in 1.5 dm³ or L), in terms of the reaction extent $x$ , we have:

$[NH_3]=0.6M=2*x$

$x=\frac{0.6M}{2}=0.3M$

Next, the concentrations of nitrogen and hydrogen at equilibrium are:

$[N_2]=\frac{1.5mol}{1.5L}-x=1M-0.3M=0.7M$

$[H_2]=\frac{4mol}{1.5L}-3*x=2.67M-0.9M=1.77M$

Therefore, the equilibrium constant is:

$Kc=\frac{(0.6M)^2}{(0.7M)*(1.77M)^3}\\ \\Kc=0.0933$

C) In this case, the equilibrium yield of ammonia is clearly 0.9 mol since is the yielded amount once equilibrium is established.

D) Here, since the reaction is endothermic (positive enthalpy change), one way to increase the yield of ammonia is increasing the temperature since heat is reactant for endothermic reactions. Moreover, since this reaction has less moles at the products, another way to increase the yield is increasing the pressure since when pressure is increased the side with fewer moles is favored.

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7 0

3 years ago

The half-life of cobalt-60 is 5. 20 yr. how many milligrams of a 2. 000 mg sample remain after 6. 55 years?

Stels [109]

0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years, according to radioactive decay.

Given data,

$t\frac{1}{2} of Co-60 = 5.20years$