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Bumek [7]
3 years ago
9

Write the chemical symbols for three different atoms or atomic cations with 10 electrons.

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

             Neon =  Ne

             Sodium Cation  =  Na⁺

             Magnesium Cation =  Mg⁺⁺

Explanation:

                  Ions are generated when an atom or of atoms gains or looses electrons. When an atom gains electrons it is converted into Anions (with -ve charge) and when it looses electrons it is converted into Cations (with +ve charge).

                  Hence, Cations are those species which contain positive charge.

As we know Neon is the noble element with atomic number 10 and contains 10 electrons in neutral state. Hence, it is the atom with 10 electrons.

While Sodium has 11 electrons in its neutral state with following electronic configuration.

                                               1s², 2s², 2p⁶, 3s¹

The valence electron in 3rd shell can be easily donated by sodium atom as the resulting stable configuration will be of a noble gas. Hence forming Na⁺.

Also, Magnesium has 12 electrons in its neutral state with following electronic configuration.

                                               1s², 2s², 2p⁶, 3s²

The valence electrons in 3rd shell can be easily donated by magnesium atom as the resulting stable configuration will be of a noble gas. Hence forming Mg⁺².

damaskus [11]3 years ago
4 0

The chemical symbols for 10 different atomic cations with 10 electrons are: Ne, Na⁺, Mg²⁺, Al³⁺

<h3><em>Further explanation </em></h3>

In an atom there are levels of energy in the skin and sub skin.

This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub skins in the skin of an atom, namely s, p, d and f. The maximum number of electrons for each sub skin is

  • s: 2 electrons
  • p: 6 electrons
  • d: 10 electrons and
  • f: 14 electrons

Charging electrons in the sub skin uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

Each sub-skin also has an orbital depicted in the form of a square in which there are electrons symbolized by half arrows.

An atom or cation that has 10 electrons means having an electron configuration as follows:

1s², 2s², 2p⁶

Judging from this configuration, the elements are in period 2 and group 8A

So the elements that meet are Ne

Whereas cations that meet 10 electrons are elements that release electrons so that they correspond to the electron configuration of the element Ne

and this element is located in period 3

This element is:

  • Na: [Ne] 3s¹

Na releases 1 electron into Na⁺ so that it matches the electron Ne configuration

  • Mg: [Ne] 3s²

Mg releases 2 electrons into Mg²⁺ so that it matches the electron Ne configuration

  • Al: [Ne] 3s² 3p1¹

Al releases 3 electrons into Al³⁺ so that it matches the electron Ne configuration

<h3><em>Learn more </em></h3>

element X

brainly.com/question/2572495

electrons and atomic orbitals

brainly.com/question/1832385

about subatomic particles statement

brainly.com/question/3176193

Keywords: electron configurations, the skin of atoms, Ne, Na⁺, Mg²⁺,Al³⁺

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So

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tia_tia [17]

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are oxidation-reduction reactions

Explanation:

In the oxidation-reduction reaction there is a component which accept electrons and it is reduced and another component which donates electrons and it is oxidized.

Now in the case of the reaction of copper (Cu) with silver nitrate (AgNO₃):

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O⁰ with a oxidation number 0 accepts 2 electrons⁻ and is transformed in O²⁻ with the oxidation number 2-.

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