Question

X+5/x^2+x-12 What are the restrictions for x

Answer 1

x ≠ - 4, 3

the denominator of the fraction cannot equal zero as this would make the fraction undefined. Equating the denominator to zero and solving gives the values that x cannot be

solve x² + x - 12 = 0

(x + 4)(x - 3) = 0

equate each factor to zero abd solve for x

x + 4 = 0 ⇒ x = - 4

x - 3 = 0 ⇒ x = 3

restrictions on x are : x ≠ - 4, 3