3 years ago

X+5/x^2+x-12 What are the restrictions for x

1 answer:

soldier1979 [14.2K]3 years ago

6 0

x ≠ - 4, 3

the denominator of the fraction cannot equal zero as this would make the fraction undefined. Equating the denominator to zero and solving gives the values that x cannot be

solve x² + x - 12 = 0

(x + 4)(x - 3) = 0

equate each factor to zero abd solve for x

x + 4 = 0 ⇒ x = - 4

x - 3 = 0 ⇒ x = 3

restrictions on x are : x ≠ - 4, 3

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Anna11 [10]

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I hope my answer has come to your help. God bless and have a nice day ahead!

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