K.e = ½mv² = ½×150×72 = 75×72 = 5400joules
The relationship between the amount of stretch or compression in an elastic object and the amount of force that is applied to that object is directly proportional to each other.
Answer:
Option B
Explanation:
Ideal elastic objects are those which will retain its original form after the removal of external force on it. So this specialty of retaining their original form after deforming due to external force is termed as elasticity. And the objects exhibiting this property is termed as elastic object. The most important law in the field of elasticity which is obeyed by all elastic object is the Hooke's law. As per Hooke's law, the external force applied on any object for deformation will be directly proportional to the changes or deformation exhibited by the object due to force. In other or simple words, the strain produced due to the external force is directly proportional to the stress acting on that object.
Stress ∝ Strain
Stress is the measure of force applied on that object and strain is the measure of amount of stretch or compression due to stress or applied force.
So option B is the correct option.
Thus, the relationship between the amount of stretch or compression in an elastic object and the amount of force that is applied to that object is directly proportional to each other.
There’s no diagram below so no can figure it out
Answer:
a) The electric potential between the cylinders,
b) The electric field between the cylinders,
Explanation:
Voltage at the inner conductor, V₁ = 20 volts
Voltage at the outer conductor, V₂ = 100 volts
Change in potential,
The change in potential is given by the formula:
The electric field,
To get the electric potential at a certain point, L from the center:
The distance from the outer conductor to the center = b - L
The electric potential at L will be given by the equation:
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