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3 years ago

Unlike images produced by a convex spherical mirror, images produced by concave spherical mirrors

Physics

2 answers:

daser333 [38]3 years ago

7 0

I think it's B, I know it's not C

Olenka [21]3 years ago

6 0

<h3>Answer;</h3>

B. can be real or virtual depending on the object's placement.

<h3>Explanation;</h3>

Unlike images produced by a convex spherical mirror, images produced by concave spherical mirrors can be real or virtual depending on the object's placement.
Concave mirror and convex mirror are two types of spherical mirrors, where a convex mirror has a reflecting surface that bulges outside while a concave mirror has a reflecting surface that bulges inwards.
Convex mirror forms images that are virtual and diminished, while a concave mirror forms an image that may either be real or virtual, diminished or enlarged depending on the position of the object from the mirror.

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You throw a ball upward with a speed of 14m/s. What is the acceleration of the ball after it leaves your hand? Ignore air resist

omeli [17]

The acceleration of the ball after leaving the hand is $9.8 m/s^2$ downward

Explanation:

In order to find the acceleration of the ball during its motion, we have to study which forces are acting on it.

After the ball leaves the hand, if we neglect air resistance, there is only one force acting on the ball: the force of gravity, whose magnitude is

$F=mg$

where m is the mass of the ball and g is the acceleration of gravity ( $g=9.8 m/s^2$ ), acting in the downward direction.

According to Newton's second law, the acceleration of the ball is given by

$a=\frac{\sum F}{m}$

where

$\sum F$ is the net force acting on the ball

After the ball leaves the hand, the only force acting on it is the force of gravity, so we can substitute (mg) into the previous equation:

$a=\frac{mg}{m}=g=9.8 m/s^2$

This means that the acceleration of the ball remains $9.8 m/s^2$ downward for the entire motion, after leaving the hand.

Learn more about Newton's second law:

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3 years ago

How can a force change the motion of an object that is already moving?

lara [203]

Answer:They may cause motion to change

Explanation:They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving. Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity.

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3 years ago

A child (approximately 4 years old) takes her metal “slinky Toy” (a flexible coiled metal spring) and does various tests to dete

anzhelika [568]

Answer:

248

Explanation:

L = Inductance of the slinky = 130 μH = 130 x 10⁻⁶ H

$l$ = length of the slinky = 3 m

N = number of turns in the slinky

r = radius of slinky = 4 cm = 0.04 m

Area of slinky is given as

A = πr²

A = (3.14) (0.04)²

A = 0.005024 m²

Inductance is given as

$L = \frac{\mu _{o}N^{2}A}{l}$

$130\times 10^{-6} = \frac{(12.56\times 10^{-7})N^{2}(0.005024)}{3}$

N = 248

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3 years ago

a car initially at rest move with the constant accerates along straght line read after it's spread increase and finally related

nasty-shy [4]

Answer:

32km per hour

Explanation:

Explanation:

In first case v = a t

==> a t = 40 km p h

Now distance covered S1 + S2 + S3

S1 = 1/2 a t^2 and S3 = 1/2 a t^2

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Hence total distance = at^2 + 120 t

Time taken (total) = t + 3t + t = 5 t

Hence average speed = at^2 + 120 t / 5 t

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victus00 [196]

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