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Sergio039 [100]

4 years ago

5

Unlike images produced by a convex spherical mirror, images produced by concave spherical mirrors

2 answers:

daser333 [38]4 years ago

7 0

I think it's B, I know it's not C

Olenka [21]4 years ago

6 0

<h3><u>Answer;</u></h3>

B. can be real or virtual depending on the object's placement.

<h3><u>Explanation;</u></h3>

Unlike images produced by a convex spherical mirror, images produced by concave spherical mirrors <em><u>can be real or virtual depending on the object's placement.</u></em>
<em><u>Concave mirror and convex mirror are two types of spherical mirrors, where a convex mirror has a reflecting surface that bulges outside while a concave mirror has a reflecting surface that bulges inwards.</u></em>
<em><u>Convex mirror forms images that are virtual and diminished, while a concave mirror forms an image that may either be real or virtual, diminished or enlarged depending on the position of the object from the mirror.</u></em>

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A 77 turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 rad/s in a 1.18 T field, starting with the normal of the

Tasya [4]

Answer:

a) fem = 5.709 V, b) t = 0.196 s, c) t = 0.589 s, d) T = 0.785 s

Explanation:

This is an exercise in Faraday's law

fem= - N $\frac{d \Phi _B}{dt}$

fem = - N $\frac{d \ (B A cos \theta)}{dt}$

The magnetic field and the area are constant

fem = - N B A $\frac{d \ cos \ \theta}{dt}$

fem = - N B A (-sin θ) $\frac{d \theta}{dt}$

fem = N B (π d² / 4) sin θ w

fem= $\frac{\pi }{4}$ N B d² w sin θ

with this expression we can correspond the questions

a) the peak of the electromotive force

this hen the sine of the angle is 1

sin θ = 1

fem = $\frac{\pi }{4}$ 77 1.18 0.10² 8.0

fem = 5.709 V

b) as the system has a constant angular velocity, we can use the angular kinematics relations

θ = w₀ t

t = θ/w₀

Recall that the angles are in radians, so the angle for the maximum of the sine is

θ= π/2

t = $\frac{\pi }{2} \ \frac{1}{8}$

t = 0.196 s

c) for the electromotive force to be negative, the sine function of being

sin θ= -1

whereby

θ = 3π/ 2

t = $\frac{3\pi }{2} \ \frac{1}{8}$

t = 0.589 s

d) This electromotive force has values that change sinusoidally with an angular velocity of

w = 8 rad / s

angular velocity and period are related

w = 2π / T

T = 2π / w

T = 2π / 8

T = 0.785 s

6 0

3 years ago

A uniform disk with radius 0.650 m

VashaNatasha [74]

Answer:

$a = 13.758\,\frac{m}{s^{2}}$

Explanation:

First, the instant associated to the angular displacement is:

$(1.10\,\frac{rad}{s} )\cdot t + (6.30\,\frac{rad}{s^{3}} )\cdot t^{2} - 0.628\,rad = 0$

Roots of the second-order polynomial are:

$t_{1} \approx 0.240\,s, t_{2} \approx -0.415\,s$

Only the first root is physically reasonable.

The angular velocity is obtained by deriving the angular displacement function:

$\omega (0.240\,s) = 1.10\,\frac{rad}{s}+ (12.6\,\frac{rad}{s^{2}})\cdot (0.240\,s)$

$\omega (0.240\,s) = 4.124\,\frac{rad}{s}$

The angular acceleration is obtained by deriving the previous function:

$\alpha (0.240\,s) = 12.6\,\frac{rad}{s^{2}}$

The resultant linear acceleration on the rim of the disk is:

$a_{t} = (0.650\,m)\cdot (12.6\,\frac{rad}{s^{2}} )$

$a_{t} = 8.190\,\frac{m}{s^{2}}$

$a_{n} = (0.650\,m)\cdot (4.124\,\frac{rad}{s} )^{2}$

$a_{n} = 11.055\,\frac{m}{s^{2}}$

$a = \sqrt{a_{t}^{2}+a_{n}^{2}}$

$a = 13.758\,\frac{m}{s^{2}}$

3 0

3 years ago

Which can give off more heat: a glass full of hot water, or a pitcher full of hot water that has the same temperature?

inessss [21]

Answer:

D

Explanation:

3 0

3 years ago

Read 2 more answers

A circuit consists of a series combination of 5.50 âkÎ© and 5.00 âkÎ© resistors connected across a 50.0-V battery having negligi

omeli [17]

Answer:

(a) 18.87 V

(b) 23.81 V

(c) 20.75%

Explanation:

The answers are given in the pictures. I have attached the pictures because circuits were needed to be drawn which are easier to understand when done on page. The page are numbered on top left corner.

7 0

4 years ago

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent

anzhelika [568]

Answer:

The position is $P = 47.4 \ m$ relative to the base of the ocean

Explanation:

From the question we are told that

The angle made by the incline with the horizontal is $\theta = 24.0 ^o$

The constant acceleration is $a = 3.82 \ m/s^2$

The distance covered is $d = 60.0 \ m$

The height of the cliff is $h = 50 .0 \ m$

The velocity of the car is mathematically represented as

$v^2 = u^2 + 2ad$

The initial velocity of the car is u= 0

So

$v^2 = 2ad$

substituting values

$v^2 = 2 * 3.82 * 60$

$v = 21.4 \ m/s$

The vertical component of this velocity is

$v_v = -v * sin(\theta )$

substituting values

$v_v = -21.4 * sin(24.0)$

$v_v = -8.7 \ m/s$

The negative sign is because is moving in the negative direction of the y-axis

The horizontal component of this velocity is

$v_h = v * cos (\theta)$

$v_h = 21.4 * cos (24.0)$

$v_h = 19.5 \ m/s$

Now according to equation of motion we have

$h = v_v*t - \frac{1}{2} * g t^2$

substituting values

$50 = -8.7 t - \frac{1}{2} * 9.8 t^2$

$4.9t^2 +8.7t -50 = 0$

using quadratic equation we have that

$t_1 = 2.42\ s \ and\ t_2 = -4.20\ s$

given that time cannot be negative

$t = 2.42 \ s$

The car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as

$P = v_h * t$

substituting values

$P = 19.5 * 2.43$

$P = 47.4 \ m$

5 0

3 years ago